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Tanya [424]
3 years ago
9

A sea turtle was

Mathematics
2 answers:
katrin2010 [14]3 years ago
4 0

Answer:

0

Step-by-step explanation:

anything below sea is negative and anything above sea level is positive. but you are at sea level so 0

deff fn [24]3 years ago
4 0

Answer:

0

Step-by-step explanation:

Because he was at -80 the they dove up positive 80 so that would equal 0

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What is the value of x? There is isosceles triangle. The measure of angle which is between two congruent sides is (6x+10⁰). The
max2010maxim [7]
<h3><u>Answer</u><u>:</u><u>-</u></h3>

x=17

<h3><u>step-by</u><u>-</u><u>step</u><u> </u><u>Explanation</u><u>:</u><u>-</u></h3>

{\boxed{\quad\:\mapsto\rm Firstly\:Let's\:understand\:the\:concept:-}}

<h3 />

This is a isosceles triangle. As it is a triangle we can apply sum theory. we have to take the sum of given unknown polynomials as 180° .Then by solving it we can find the value of x.

<h3><u>Solution</u><u>:</u><u>-</u></h3>

Given angles

  • (6x+10°)
  • (x+17°)
  • (4x-34)°

According to sum theory

{\boxed{\sf The \:sum\:of\:angles=180°}}

  • Substitute the values

\qquad \quad{:}\longmapsto\tt (6x+10)+(x+17)+(4x-34)=180

  • Remove brackets

\qquad \quad{:}\longmapsto\tt 6x+10+x+17+4x-34=180

  • Together like polynomials and constants

\qquad \quad{:}\longmapsto\tt 6x+x+4x+10+17-34=180

\qquad \quad{:}\longmapsto\tt 11x-7=180

  • Interchange sides

\qquad \quad{:}\longmapsto\tt 11x=180+7

\qquad \quad{:}\longmapsto\tt 11x=187

\qquad \quad{:}\longmapsto\tt x=\cancel{\dfrac{187}{11}}

  • Simplify

\qquad \quad{:}\longmapsto\tt x=17

\therefore\sf The \:value\:of\:x\;is\:17.

8 0
3 years ago
15 POINTS!!!<br><br> I just need to know if I do 1 4/9 - 1 8/11 or the other way around very simple!
Verdich [7]
<h3>- - - - - - - - - - - - - - - ~<u>Hello There</u>!~ - - - - - - - - - - - - - - - </h3>

➷ You need to do 1 \frac{8}{11} - 1\frac{4}{9}

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ Hannah ♡

5 0
3 years ago
Read 2 more answers
What is 24x128725(7x782)/199+4+23
ryzh [129]

Answer:

\bold{\frac{8455687800}{113}}

Step-by-step explanation:

\frac{24\times \:128725\left(7\times \:782\right)}{199+4+23}

\mathrm{Add\:the\:numbers:}\:199+4+23=226

=\frac{24\times \:128725\times \:7\times \:782}{226}

\mathrm{Factor\:the\:number:\:}\:24=2\times \:12

=\frac{2\times \:12\times \:128725\times \:7\times \:782}{226}

\mathrm{Factor\:the\:number:\:}\:226=2\times \:113

=\frac{2\times \:12\times \:128725\times \:7\times \:782}{2\times \:113}

\mathrm{Cancel\:the\:common\:factor:}\:2

=\frac{12\times \:128725\times \:7\times \:782}{113}

\mathrm{Multiply\:the\:numbers:}\:12\times \:128725\times \:7\times \:782=8455687800

\bold{=\frac{8455687800}{113}}

\mathrm{Decimal:74829095.57522}

5 0
3 years ago
I need help asap plz I will mark branlist promise
anygoal [31]

Assuming none of the factors is zero, if an odd number of the factors of a multiplication problem have negative signs, then the product will be negative. Otherwise, the product is positive.

Assuming the dividend of a division problem is non-zero, the quotient wil be negative if the signs of the dividend and divisor are differnt. Otherwise the quotient is positive.

In short, if a multiplication or division problem involves an odd number of minus signs, the result will be negative. Otherwise, the result is positive.

5 0
3 years ago
Suppose that f'(4) = 3 , g'(4) = 7 , g(4) = 4 and g(x) not= to 4 for xnot= to 4 . then cmpute lim xgose to 4 f(g(x))/x-4-f(4)/x-
Rus_ich [418]

It looks like the limit you want to compute is

\displaystyle \lim_{x\to4} \frac{f(g(x)) - f(4)}{x-4}

Since g(4)=4, this limit corresponds exactly to the derivative of (f\circ g)(x) = f(g(x)) at x=4. Recall that

f'(a) = \displaystyle \lim_{x\to a} \frac{f(x) - f(a)}{x - a}

By the chain rule,

(f\circ g)'(4) = f'(g(4)) \times g'(4) = f'(4) \times g'(4) = 3\times7 = \boxed{21}

Since g'(4) exists, g is differentiable at x=4 so it must be continuous.

4 0
2 years ago
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