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Mkey [24]
3 years ago
6

What is the independent and dependent variable?

Chemistry
1 answer:
vladimir1956 [14]3 years ago
4 0

Answer:

The independent and dependent variable for the following are as follows:

a. Temperature and amount of dissolved oxygen

b. pH and SO2 solubility/amount

c. H2SO4 concentration and voltage output/performance of battery

Explanation:

In an experiment;

- Independent variable is the variable that the experimenter manipulates or changes in order to get a measurable response.

- Dependent variable is the variable that the experimenter measures based on its response to changes made to the independent variable.

A). In this experiment, a student is trying to investigate the amount of dissolved oxygen in a local pond in response to changes in temperature. Hence, the independent variable is the TEMPERATURE while the dependent variable is the AMOUNT OF DISSOLVED OXYGEN.

B). In this experiment, a wine producer would like to explore if pH affects the solubility of SO2 in the wine by measuring the amount of SO2 in the wine solution over a range of pH values. Hence, the independent variable is the pH while the dependent variable is the SO2 SOLUBILITY OR AMOUNT.

C). In this experiment, a researcher wishes to determine the optimal H2SO4 concentration for the best performance of the battery, as measured by the voltage output. Hence, the independent variable is the CONCENTRATION OF H2SO4 while the dependent variable is the VOLTAGE OUTPUT or PERFORMANCE of the battery.

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Pani-rosa [81]

The question is incomplete, here is the complete question:

What volume (mL) of the partially neutralized stomach acid having concentration 2M was neutralized by 0.01 M NaOH during the titration? (portion of 25.00 mL NaOH sample was used; this was the HCl remaining after the antacid tablet did it's job)

<u>Answer:</u> The volume of HCl neutralized is 0.125 mL

<u>Explanation:</u>

To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HCl (Stomach acid)

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=1\\M_1=2M\\V_1=?mL\\n_2=1\\M_2=0.01M\\V_2=25mL

Putting values in above equation, we get:

1\times 2\times V_1=1\times 0.01\times 25\\\\V_1=\frac{1\times 0.01\times 25}{1\times 2}=0.125mL

Hence, the volume of HCl neutralized is 0.125 mL

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Need help here plz ASAP!!!!!!!!
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Three! 3

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O2 means that there are two oxygen and I is just one

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