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2 years ago

Need help here plz ASAP!!!!!!!!

Chemistry

2 answers:

Alekssandra [29.7K]2 years ago

8 0

Answer:

Three! 3

Explanation:

O2 means that there are two oxygen and I is just one

xxMikexx [17]2 years ago

4 0

Answer:

Explanation:

First one is compound

The second one is three

The third one is so dissolving in a glass of water

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What is the relative atomic mass of an element

Gennadij [26K]

Answer:

20.2 amu.

Explanation:

Let A represent isotope ²⁰X

Let B represent isotope ²²X

From the question given above, the following data were obtained:

For Isotope A (²⁰X):

Mass of A = 20

Abundance (A%) = 90%

For Isotope B (²²X):

Mass of B = 22

Abundance (A%) = 10%

Relative atomic mass (RAM) =?

The relative atomic mass (RAM) of the element can be obtained as follow:

RAM = [(Mass of A × A%)/100] + [(Mass of B × B%)/100]

RAM = [(20 × 90)/100] + [(22 × 10)/100]

RAM = 18 + 2.2

RAM = 20.2 amu

Thus, relative atomic mass (RAM) of the element is 20.2 amu

4 0

2 years ago

⚠️HELP DUE IN 10 MINS WILL GIVE BRAINLIEST!!! THANKS⚠️

LenKa [72]

Answer:

hahahh noob

Explanation:

3 0

3 years ago

Mass of water using isotopes? The water found on Earth is almost entirely made up of the ^1H and ^{16}O isotopes for a formula o

jenyasd209 [6]

Thank you for posting your question here brainly. Based on the problem mentioned above the largest mass that water molecule could have using other isotopes is <span>24 amu. Below is the solution, I hope the answers helps.

</span><span>T2_18O = 24</span>

7 0

2 years ago

Read 2 more answers

What is the mass of a sample of alcohol (specific heat = 2.4 J/gC), if it requires 4780 J of heat to raise the temperature by 5.

insens350 [35]

The mass of a sample of alcohol is found to be = m = 367 g

Hence, it is found out that by raising the temperature of the given product, the mass of alcohol would be 367 g.

Explanation:

The Energy of the sample given is q = 4780

We are required to find the mass of alcohol m = ?

Given that,

The specific heat given is represented by = c = 2.4 J/gC