Easily over <span>120000 , I do not think their are any statistic or too accurate sources to go by but it is a estimate.</span><span />
Answer: 0.7973
Explanation:
Binomial probability formula :-
, where P(x) is the probability of getting success in x trials , p is the probability of success in one trial and n is the number of trials.
Given : The probability of getting a defect components : 
If randomly select and test 26 components , then the probability that this whole shipment will be accepted will be :-
Hence, the probability that this whole shipment will be accepted = 0.7973
Answer: A.) $1,095
Explanation:
Bond value = $30,000
Rate = 7%
Period = 10 years
Issue price = $29,100
Bond value × rate :
30,000 × 0.07 = $2100
Semi annually:
$2100 / 2 = $1050
(Bond value - issue price) ÷ (period × 2)
($30,000 - $29,100) / (10 × 2)
$900 ÷ 20 = $45
$1050 + $45 = $1,095
Answer:
The production range between 1120,000 and 150,000 is called Relevant range
correct option is c) relevant range
Explanation:
given data
normally produces = 120,000 to 150,000 units
to find out
The production range between 1120,000 and 150,000 is called
solution
The production range between 1120,000 and 150,000 is called Relevant range because there are 2 point
- if Craft, Inc. need to reduce fixed expenses then production volume is reduce less than 120000 unit
- if Craft, Inc. need to increase fixed expenses than production volume is increases more than 150000 unit
and if expected fixed expenses will not change than the production volume is 120000 units to 150000 units
so that production range between 1120,000 and 150,000 is called Relevant range
correct option is c) relevant range
Answer:
maximum profit = $7500
so correct option is c $7500
Explanation:
given data
mean = 500
standard deviation = 300
cost = $10
price = $25
Inventory salvaged = $5
to find out
What is its maximum profit
solution
we get here maximum profit that is express as
maximum profit = mean × ( price - cost ) ..................................1
put here value in equation 1 we get maximum profit
maximum profit = mean × ( price - cost )
maximum profit = 500 × ( $25 - $10 )
maximum profit = 500 × $15
maximum profit = $7500
so correct option is c $7500
