All categories

3 years ago

Help will mark brainliest!!

Mathematics

1 answer:

Ira Lisetskai [31]3 years ago

3 0

110 should be the answer 189 minus 70 is 110 always when involved with triangles use 180 to start with then subtract what’s there .

You might be interested in

EYEWITNESS TESTIMONY. A man was struck by a speeding taxi as he crossed the street. An eyewitness testified the taxi (which did

Brrunno [24]

Answer:

The probability the man was hit by a Blue Cab taxi is 41%.

Step-by-step explanation:

In terms of bayesian probability, we have to calculate P(B|Wr), or, given the witness saw the right colour, the taxi is from the Blue Cab company.

According to Bayes

P(B|Wr) = P(Wr|B)*P(B)/P(Wr)

P(Wr|B) = 0,8

P(B) = 0.15

To calculate P(Wr), or the probability of the witness of guessing right, we have to consider the two possibilities:

1) The taxi is from Blue Cab (B) and the witness is right (Wr).

2) The taxi is from Green Cab (G) and the witness is wrong (Ww).

The total probality of guessing right is

P(B)*P(Wr) + P(G)*P(Ww) = 0.15*0.8 + 0.85*0.2 = 0.29

So we can calculate:

P(B|Wr) = P(Wr|B)*P(B)/P(Wr) = 0.8*0.15/0.29 = 0.41

The probability the man was hit by a Blue Cab taxi is 41%.

4 0

3 years ago

HELLLLP (will mark brainiest)

Zigmanuir [339]

Answer:

We put the value of the x in the formula

${4 \times }(6)^{2} - 7 \times 6 + 12$

f(6)=

$4 \times 36 - 7 \times 6 + 12 = 144 - 42 + 12 = 102 + 12 = 114$

Step-by-step explanation:

Than solve equation.

6 0

3 years ago

Read 2 more answers

If a and b are two angles in standard position in Quadrant I, find cos(a+b) for the given function values. sin a=8/17and cos b=1

n200080 [17]

Recall the sum identity for cosine:

cos(a + b) = cos(a) cos(b) - sin(a) sin(b)

so that

cos(a + b) = 12/13 cos(a) - 8/17 sin(b)

Since both a and b terminate in the first quadrant, we know that both cos(a) and sin(b) are positive. Then using the Pythagorean identity,

cos²(a) + sin²(a) = 1 ⇒ cos(a) = √(1 - sin²(a)) = 15/17

cos²(b) + sin²(b) = 1 ⇒ sin(b) = √(1 - cos²(b)) = 5/13

Then

cos(a + b) = 12/13 • 15/17 - 8/17 • 5/13 = 140/221

6 0

2 years ago

Sin theta+costheta/sintheta -costheta+sintheta-costheta/sintheta+costheta=2sec2/tan2 theta -1

sleet_krkn [62]

$\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}=\dfrac{2sec^2\theta}{tan^2\theta-1}$

From Left side:

$\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}\bigg(\dfrac{sin\theta+cos\theta}{sin\theta+cos\theta}\bigg)+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}\bigg(\dfrac{sin\theta-cos\theta}{sin\theta-cos\theta}\bigg)$

$\dfrac{sin^2\theta+2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}+\dfrac{sin^2\theta-2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}$

NOTE: sin²θ + cos²θ = 1

$\dfrac{1 + 2cos\theta sin\theta}{sin^2\theta-cos^2\theta}+\dfrac{1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}$

$\dfrac{1 + 2cos\theta sin\theta+1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}$

$\dfrac{2}{sin^2\theta-cos^2\theta}$

$\dfrac{2}{\bigg(sin^2\theta-cos^2\theta\bigg)\bigg(\dfrac{cos^2\theta}{cos^2\theta}\bigg)}$

$\dfrac{2sec^2\theta}{\dfrac{sin^2\theta}{cos^2\theta}-\dfrac{cos^2\theta}{cos^2\theta}}$

$\dfrac{2sec^2\theta}{tan^2\theta-1}$

Left side = Right side <em>so proof is complete</em>

8 0

3 years ago

Read 2 more answers

The probability of having a winning raffle ticket is 20%. If you bought 50 tickets, how many winning tickets should you expect t

Usimov [2.4K]

$\frac{20}{100} = \frac{x}{50}$
Let's solve for x:
100x=1000
Divide by 100
x=10
You should expect to win 10 times.

3 0

3 years ago

Read 2 more answers