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3 years ago

Which atorn was used to determine the amount of particles in a mole?

Chemistry

1 answer:

stich3 [128]3 years ago

5 0

Answer:

carbon atom is used to determine the amt of particles in a mole

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3 years ago

What is a scientific word for baking soda

igor_vitrenko [27]

Sodium bicarbonate is commonly known as baking soda. The scientific name is NaHCO3. Baking soda is an alkaline compound found in crystalline form in nature.

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3 years ago

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Isocyanic acid, also known as Hydrogen cyanate, is a weak acid and a potentially toxic atmospheric pollutant. Write down the equ

densk [106]

The dissociation of isocyanic acid in water produces its conjugate base, C N- since it will accept a proton to form isocyanic acid.

<h3>What is a conjugate base?</h3>

A conjugate base is a substance which is formed from the loss of the hydrogen ion of an acid and which will act as a base by accepting a proton.

The dissociation of Isocyanic acid in water is given below:

$HC N + H_2O \rightleftharpoons C N^{-} + H_3O^{+}$

The conjugate base is C N- since it will accept a proton to form isocyanic acid.

Learn more about conjugate base at: brainly.com/question/22514615

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3 years ago

Se hacen reaccionar 100 g del agente oxidante con 25 g del agente reductor, según la reacción REDOX LaTeX: N_2\left(g\right)+H_2

Vesna [10]

Answer:

El reactivo en exceso es hidrógeno

97.12g NH₃ son formados

Explanation:

Basados en la reacción:

N₂(g) + 3 H₂(g) → 2 NH₃(g)

El hidrógeno pasa de estado de oxidación 0 a estado de oxidación +1. Al perder un electrón se oxida y es el agente reductor.

El nitrógeno pasa de estado 0 estado -3. Al ganar 3 electrones se reduce y es el agente oxidante.

100g de N₂ son (Peso molecular: 28g/mol):

100g × (1mol / 28g) = 3.57 moles de N₂

Y 25g de H₂ son (Peso molecular: 2g/mol):

25g × (1mol / 2g) = 12.5 moles de H₂

Como 3 moles de hidrógeno reaccionan por mol de nitrógeno, las moles de nitrógeno que se necesitan para hacer reaccionar completamente 12.5 moles de hidrógeno son:

12.5 moles H₂× (1 mol N₂ / 3 moles H₂) = 4.17 moles de nitrógeno.

Como hay 3.57 moles de nitrógeno, el reactivo en exceso es hidrógeno.

Como el reactivo limitante es el nitrógeno y 1 mol de nitrógeno produce 2 moles de amoniaco, las moles de amoniaco son:

3.57 moles de N₂ × (2 moles NH₃ / 1 mol N₂) = 7.14 moles de NH₃

La masa producida idealmente es:

7.14 mol NH₃ ₓ (17g/mol) = 121.4 g de NH₃. Como la eficiencia del proceso es del 80%:

121.4 g NH₃ × 80% = 97.12g NH₃ son formados

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3 years ago

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