Whereas sodium is found mainly in the extracellular fluid, most ________ is found in the intracellular fluid.A) ironB) chlorideC
1 answer:
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Answer:
0.15g
Explanation:
Given parameters:
Number of molecules of water = 1.2 x 10²¹ molecules
Unknown:
Mass of SnO₂ = ?
Solution:
To solve this problem, we have to work from the known to the unknown specie;
SnO₂ + 2H₂ → Sn + 2H₂O
Ensure that the equation given is balanced;
Now,
the known species is water;
6.02 x 10²³ molecules of water = 1 mole
1.2 x 10²¹ molecules of water = = 0.2 x 10⁻²moles
Number of moles of water = 0.002moles
From the balanced chemical equation:
2 mole of water is produced from 1 mole of SnO₂
0.002 moles of water will be produced from = 0.001moles
To find the mass;
Mass = number of moles x molar mass
Molar mass of SnO₂ = 118.7 + 2(16) = 150.7g/mol
Mass = 0.001 x 150.7 = 0.15g
Answer : The correct option is, (B) 0.11 M
Solution :
First we have to calculate the concentration and
.
The given equilibrium reaction is,
Initially 0.70 0.70 0
At equilibrium (0.70-x) (0.70-x) x
The expression of will be,
Now put all the given values in the above expression, we get:
By solving the term x, we get
From the values of 'x' we conclude that, x = 0.83 can not more than initial concentration. So, the value of 'x' which is equal to 0.83 is not consider.
Thus, the concentration of at equilibrium = (0.70-x) = (0.70-0.59) = 0.11 M
The concentration of at equilibrium = (0.70-x) = (0.70-0.59) = 0.11 M
The concentration of at equilibrium = x = 0.59 M
Therefore, the concentration of at equilibrium is 0.11 M
Answer:
Explanation:
Hello!
In this case, since a dilution process implies that the moles of the solute remain the same before and after the addition of diluting water, we can write:
Thus, since we know the volume and concentration of the initial sample, we compute the resulting concentration as shown below:
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