A is the answer im pretty sure
Answer:
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Explanation:
Answer:
C6H14 < C6H13Br < C6H13OH < C6H12(OH)2
Explanation:
Hello,
In this case, since the solubility in water is related with the presence of polar bonds in the given molecules we can see that C6H12(OH)2 has the presence two O-H bonds which promote the highest solubility via hydrogen bonds as well as the C6H13OH but in a lower degree as only on O-H bond is present. Next since the bond C-Br in is slightly close to the polar bond C6H13Br rather than the C-C bonds only had by C6H14 we can infer that C6H13Br is more soluble in water than C6H14, therefore the required order is:
C6H14 < C6H13Br < C6H13OH < C6H12(OH)2
Whereas C6H12(OH)2 is the most soluble and C6H14 the least soluble in water.
Best regards.
Answer:
The balance equation is
→ 
Explanation:
first, we have to make sure that the atoms are balanced
→ 
→ 
then we proceed to balance charges of each half-reaction
→
→ 
Now we multiply the half-reactions to match the number of electrons in each one
( → )x2
( → )x3
and now we do the sum of the half-reactions
2
→ 2
→ 3 
→
note: the only atom that needed to be balanced was I
