Volume of 1 mol of gas at standard temperature and pressure is 22.4 L.
That is using ideal gas equation:
PV = nRT
P=pressure
V=volume
n=number of moles
R=gas constant
T=temperature
at STP,
P=1 atm
T=273K
n=1(given)
Putting all the values in the equation will give,
V= 22.4 L
So, the answer is :
The volume of 1 mol of gas at standard temperature and pressure is 22.4 L.
3 Common States of Matter:
1. Solid - particles are motionless and stick together very closely.
2. Liquid - particles are moving slowly without pattern.
3. Gas - Particles are moving rapidly again without pattern.
gas = methane
burn with O₂ (oxygen)
CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(l)
Answer:
6 moles of oxygen, or 3O2.
Explanation:
I would build a proportion for this:
Answer:
The answer to your question is: 0.25 l
Explanation:
Data
P1 = 1 atm
V1 = 0.5 l
P2 =2 atm
V2 = ?
T = constant
Formula
V1P1 = V2P2
Clear V2 from the formula
V2 = V1P1/P2
Substitution
V2 = (0.5)(1)/2 substitution
= 0.25 l result
