Answer:
1. 18.84 in
2. 56.52 cm
3. 4.71 ft
4. 25.12 m
5. 37.68 ft
6. 12.56 yd
7. 43.96 in
8. 28.26 cm
9. 7.85 m
Step-by-step explanation:

Answer:
This statement is true
Step-by-step explanation:
Answer:
The value of E(Y/X) is 2.
Step-by-step explanation:
As the complete question is not given, thus the complete question is found online and is attached herewith.
So the joint density function is given as

So the marginal function for X is given as

Now

Now the value of E(Y/X) is given as

So the value of E(Y/X) is 2.
Answer:
yes
Step-by-step explanation: