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densk [106]
3 years ago
12

Zoey can tile 1 1/4 square yards in 1/3 hour. What is her unit rate?

Mathematics
1 answer:
alukav5142 [94]3 years ago
5 0
We know that Zoey can tile 1.25 square yards in 20 minutes (which is 1/3 of an hour) so we wanna see how much she can tile in an hour. Multiply 1.25 by 3.

1.25•3= 3.75 or 3 3/4
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Z^4-4z^3+4z^2+48=0 how to find value of z?​
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Can the mean (average) be greater than the largest number in a data set?
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3 years ago
Please Help ASAP! I suck at geometry :(
ZanzabumX [31]

We know that for every 5 red bricks there were 2 gray bricks.

The total amount of red bricks and grey bricks in this sample is 7.

5 red bricks + 2 grey bricks = 7 bricks

Now, we divide 175 "total number of bricks used" by 7 "5 red bricks + 2 grey bricks = 7 bricks" and we will get a quotient of 25.

Now we know that 25 bricks is \frac{1}{7} of the wall. The gray bricks are \frac{2}{7} so we can multiply 25 by 2 and we will get a product of 50. If 1/7 = 25 grey bricks so 2/7 would be the grey bricks.

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8 0
3 years ago
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Simplify 2k^8×3k^3 <br>​
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4 years ago
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I need to make a matrix in reduced row echelon form
a_sh-v [17]

Let the three apartments be A, B & C

The rent of A is $x

The rent of B is $y

The rent of C is $z

So x + y + z = 1600     .......(1)

Now

Maintenance of A is 20% of x = 0.20x

Maintenance of B is 20% of y = 0.20y

Maintenance of C is 25% of z = 0.25z

0.20x + 0.20y + 0.25z = 345

Multiplying by 100 we get

20x + 20y + 25 z = 34500

Dividing by 5 we get

4x + 4y + 5z = 6900              .......(2)

Monthly fee of A is 10% of x = 0.10x

Monthly fee of B is 20% of y = 0.20 y

Monthly Fee of C is 10% of z = 0.10z

Now

0.10x + 0.20y + 0.10 z= 1820 - 1600

0.10x + 0.20y + 0.10z = 220

Multiplying by 100 we get

10x + 20y + 10z = 22000

Dividing by 10

x + 2y + z = 2200     ....(3)

Making a Matrix of equation (1), (2) & (3)

\left[\begin{array}{ccc}1&1&1\\4&4&5\\1&2&1\end{array}\right] \left[\begin{array}{c}x\\y\\z\end{array}\right]  =\left[\begin{array}{c}1600\\6900\\2200\end{array}\right]

is the required matrix

7 0
4 years ago
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