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2 years ago

Zoey can tile 1 1/4 square yards in 1/3 hour. What is her unit rate?

1 answer:

5 0

We know that Zoey can tile 1.25 square yards in 20 minutes (which is 1/3 of an hour) so we wanna see how much she can tile in an hour. Multiply 1.25 by 3.

1.25•3= 3.75 or 3 3/4

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Three babies A,B and C cry out at interval time. Baby A cries out at every 20 mins, while B cries out at every 30 mins and C cri

Kaylis [27]

They all cried 210 minutes if u want it in hrs divide

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2 years ago

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Tess plants flowers every year, and she noticed that her flowers tend to bloom earlier when the spring weather is warmer. She co

OlgaM077 [116]

Answer:

=17

Step-by-step explanation:

We need the slope and the y-intercept to find the equation of the linear model.

This line goes through (0,28) and (1,26), so the slope is

\frac{26 - 28}{1} = -2

26−28

=−2

The equation that best describes this model is

\widehat{y} = -2x + 28

=−2x+28

Plug in x = 5.5 in the above equation to get

\widehat{y}

=−2x+28

=(−2)(5.5)+28

=−11+28

=17

Based on this equation, the date in April her flowers will bloom if the average temperature in March is

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2 years ago

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Draw a number line please

Mkey [24]

Answer:

1 2 3 4 5 6 7 8 9 10.... etc

Step-by-step explanation:

What number goes between the numbers that I put.

6 0

2 years ago

What is another way to group the factors (3×2)×5

olasank [31]

<h2>3*(2*5)</h2><h2>2*(3*5) is the correct groupings </h2><h2 />

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3 years ago

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Does anyone know this?

Stels [109]

Every hexagon clearly has 6 sides. Nevertheless, every time you "glue" two hexagons together, you "lose" 2 sides to your count, because the sides where the two hexagons meet are not exterior sides anymore, and so they are not taken into account in our counting.

Also observe that with n hexagons you have n-1 points of contact between hexagons.

Since every hexagon has 6 sides and every gluing point takes away 2 sides, the number of exterior sides with n hexagons is

$s(n)=6n - 2(n-1) = 6n-2n+2=4n+2$

Let's plug some values for n:

$s(1) = 4\cdot 1 + 2 = 4+2 = 6$
$s(2) = 4\cdot 2 + 2 = 8+2 = 10$
$s(3) = 4\cdot 3 + 2 = 12+2 = 14$
$s(4) = 4\cdot 4 + 2 = 16+2 = 18$

You can check that these values are correct by counting the sides on the figure you have.

Finally, we can count the sides of a train with 10 hexagons by plugging n=10 in our formula:

$s(10) = 4\cdot 10 + 2 = 40 + 2 = 42$

Note: the numbers we've given are the number of sides that form the perimeter. So, the actual perimeters are the number of sides multiplied by the length of the side itself: if we let $s$ be the length of the side, the perimeters will be $6s,\ 10s,\ 14s,\ 18s$ for the first 4 trains, and $42s$ for the 10-hexagon train.

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3 years ago