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KengaRu [80]
3 years ago
15

Can someone help with this?

Mathematics
1 answer:
Alex73 [517]3 years ago
3 0
What do you need help with
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In how many games did the team score at least 70 points?
Anarel [89]
At least 70 points, so 70 or more points. Therefore 5 games: 71, 71, ,72, 73 and 91 points
7 0
3 years ago
This shows the template for a diamond-shaped mirror frame. (View attachment)
Tomtit [17]

Answer:

We know that the area of a square of side length L is given by:

A = L^2

Here, the total area of the white square is:

A = (3x + 1)^2

And the area of the shaded square is:

A' = (2x + 3)^2

a) If we remove the shaded area from the white area, the remaining area is just the difference between the two, then:

area = A - A' =  (3x + 1)^2 - (2x + 3)^2

This is the expression we wanted.

b) Now we need to expand and simplify the expression:

area = (3x + 1)^2 - (2x + 3)^2

area = (3x)^2 + 2*(3x)*1 + 1^2 - (2x)^2 - 2*(2x)*3 - 3^2

area = 9x^2 + 6x + 1 - 4x^2 - 12x - 9

area = (9 - 4)*x^2 + (6 - 12)*x + 1 - 9

area = 5*x^2 - 6*x - 8

This is the simplified equation for the remaining area.

8 0
3 years ago
Melinda and Marcus each have a job. Melinda earns $12 an hour. She also receives a $75 weekly bonus.
Olenka [21]
According to given information,
Equation of Melinda Earning = 75 + 12x
Equation of Marcus Earning = 15x
Where, x = Number of hours they worked.

Now, we need to calculate when they will have same amount of money, so for that instance they shall equal to each other.
75 + 12x = 15x
15x - 12x = 75
3x = 75
x = 75/3
x = 25

After 25 hours, they will have the money = 15(25) = $375

So, your final answer is $375

Hope this helps!

8 0
3 years ago
Read 2 more answers
Fiona can type 60 words a minute. <br> How many words can be typed in 10.5 minutes?
Nina [5.8K]

Answer:

630 word

10.5 minute: 10×60+0.5×60=600+30=630 second

60 word 60second

? word 630 second

?=630

5 0
3 years ago
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Can a quadratic have one real and one non real root
alukav5142 [94]

Answer:

Yes, it is possible. We already know that complex roots exist in conjugate pair but the case is true only when the equation has real coefficients. But on the other hand, if the equation has complex coefficients, then it is possible to attain one real and one complex root.

3 0
3 years ago
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