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KengaRu [80]
3 years ago
15

Can someone help with this?

Mathematics
1 answer:
Alex73 [517]3 years ago
3 0
What do you need help with
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Change the subject of the equation v = u + at to a.
emmasim [6.3K]
<h3>Answer ↓</h3>

<h3>Calculations ↓</h3>

In order to make a the subject of this equation , we need to get a by itself .

The current equation is :

v = u + at

Subtract u on both sides :

v-u=at

Now, divide by t on both sides :

v-u/t=a

<h3>So the formula looks like ↓</h3>

\boxed{\\\begin{minipage}{3cm}Equation \\ a=$\displaystyle\frac{v-u}{t} $ \\ \end{minipage}}

hope helpful ~

8 0
2 years ago
Given ABCD is a parallelagram diagonals AC and BD intersect at E Prove AE is congruent to CE and BE is congruent to DE
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In the parallelogram ABCD, diagonals AC and BD intersect at point E.

According to the definition of parallelogram, opposite sides are equal and parallel to each other. That means, AB = DC

Now as AB and DC are parallel, so according to the property of Alternate Interior Angles, we will get:

∠EAB = ∠ECD and ∠EBA = ∠EDC

Thus , in two triangles ΔABE and ΔDCE, two angles and one side are equal. So, ΔABE and ΔDCE are congruent to each other.

That means, AE = CE and BE = DE

So, AE is congruent to CE and BE is congruent to DE

8 0
3 years ago
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