Rewrite the equation in slope intercept form:
Y -6 = -3(x - -8)
Use the distributive property on the right side first:
Y -6 = -3x -24
Add 6 to both sides
Y = -3x -18
The slope is the number in front of the x variable.
Slope = -3
Answer:
13/102
Step-by-step explanation:
In a standard deck of 52 cards, there are 13 black spades, 13 black clubs, 13 red diamonds and 13 red hearts. There are 26 <u>black </u>cards in the deck of 52 cards.
Probability of drawing a black card = 26/52 = 1/2
Suppose we drew the black card. There are now <u>only 51</u> cards left in the deck. ALL of the hearts are still there - <u>13</u> of them.
Probability of drawing a heart from this deck of 51 = 13/51
In general, for the probability of event A <u>and then</u> event B, we multiply.
1/2 x 13/51 = 13/102
Okay, take a look at diagram 1 (I know it's rubbish I did it on paint :D), this shows all the information you've given in the question. The two coordinates and the distance between them.
Now if we draw additional lines on this diagram, we can make a right-angled triangle (this is on diagram 2). We can also work out the lengths of the additional sides because we know both coordinates at the end-points of the additional lines.
Finally because this is a right-angled triangle, Pythagoras' theorem must apply to its sides meaning



therefore x=5.
Answer:
x = 5/(10 - a - b)
Step-by-step explanation:
Solve for x:
4 + 3 x - a x = 9 - 7 x + b x
Collect in terms of x:
x (3 - a) + 4 = 9 - 7 x + b x
Collect in terms of x:
x (3 - a) + 4 = x (b - 7) + 9
Subtract (b - 7) x + 4 from both sides:
x (10 - a - b) = 5
Divide both sides by 10 - a - b:
Answer: x = 5/(10 - a - b)
<span>A)2x^2+3 is a transformation of f(x)=x^2: Stretch the graph vertically by a factor of 2 and then shift the entire resulting graph up by 3 units. The graph will still look like a parabola that opens up.
</span>B)-2x^2-3 is a transformation of f(x)=x^2: Stretch the graph vertically by a factor of 2, reflect the resulting graph in the x-axis, and then shift the entire resulting graph down by 3 units. The graph will still look like a parabola that opens down.
<span>
Answers to C and D are very similar, except that we compress the graph of x^2 v ertically by a factor of (1/2).
None of these A, B, C, D is wrong.
</span>