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lbvjy [14]
3 years ago
9

En un barrio un estudiante observa un roedor en medio de dos postes, los cuales están comunicados por un solo cable de fibra ópt

ica, el cual calcula que tiene 50 m de longitud de poste a poste. Dicho roedor al estar apoyado pandea el cable 0.058 m. Si el estudiante intuye, que por sus clases de bilogía el roedor tiene aproximadamente 350gde masa, ¿Cuál será la tensión del cable debido a dicho suceso?
Physics
1 answer:
castortr0y [4]3 years ago
4 0

Answer:

7 Newton

Explanation:

Dado

Longitud de la cuerda = 50 m

El cable se dobla en 0,058 m.

Masa de roedor = 350 gramos = 0,35 kg

T = m * a + m × v2 / r

Sustituyendo los valores dados obtenemos

T = 0,35 (10 + 10)

T = 0,35 * 20

T = 7 Newton

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Answer:

v=15.24 m/s

Explanation:

Given that

Mass ,m= 1600 kg

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Coefficient of friction ,μ = 0.83

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F=\dfrac{mv^2}{r}

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Fr= μ m g

The condition for motion without losing traction

F= Fr

\dfrac{mv^2}{r}=\mu\ m g

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v=15.24 m/s

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Luz, who is skydiving, is traveling at terminal velocity with her body parallel to the ground. She then changes her body positio
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Answer:

Option C - she will speed up because air resistance has reduced and be less than gravity

Explanation:

We are told that Luz is skydiving with terminal velocity and her body parallel to the ground. Now, at this point she will be experiencing a gravitational force acting downwards, and also air resistance as a result of the drag force on her body

Since the downward gravitational force on Luz is constant, she will fall with a net force of;

F_net = F_g - F_d

where;

F_net is the net force on Luz acting downwards

F_g is the gravitational force on Luz

F_d is the drag force on Luz

The drag force on her body is proportional to the surface area of attack.

We are now told that Luz changes her body position to feet first toward the ground. This means that the surface area of attack is reduced because the feet will consume less space than the frontal part of her body. Thus, the drag force will be lesser then before she changed her body position due to reduced air resistance on her body.

Now, from earlier, we saw that;

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So, the lesser F_d is, the higher F_net becomes.

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4 years ago
A bullet of mass 0.0021 kg initially moving at 497 m/s embeds itself in a large fixed piece of wood and travels 0.65 m before co
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Answer:

The force exerted by the wood on the bullet is 399.01 N

Explanation:

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initial velocity of the bullet, u = 497 m/s

final velocity of the bullet, v = 0

distance traveled by the bullet, S = 0.65 m

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F = ma

F = 0.0021 x 190006.92

F = 399.01 N

Therefore, the force exerted by the wood on the bullet is 399.01 N

6 0
3 years ago
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