Is the term used to describe the removal of sand and soil by the wind.

Suppose that after walking across a carpeted floor you reach for a doorknob and just before you touch it a spark jumps 0.95cm fr

alexandr402 [8]

To solve this problem we will consider the definition of Minimum Energy, as the change between the minimum voltage and its distance. Mathematically it can be written as

$E_{min} = \frac{V_{min}}{r}$

Rearranging to find the Voltage,

$V_{min} = E_{min} \times r$

Replacing,

$V_{min} = (3.0) \times (0.95*10^4)$

$V_{min} = 28500V$

Therefore the minimum voltage needed between your finger and the doorknob to generate this spark is 28.5kV

8 0

3 years ago

A dog runs with an initial speed if 7.5m/s on a waxed floor. it slides to a stop in 15 seconds. What is the acceleration

kap26 [50]

Answer:

The answer is -0.5m/s2

Explanation:

I did the test and got it right.

6 0

3 years ago

List some ways houses would be built differently if gravity were much stronger or much weaker ?two

tia_tia [17]

Answer:

If gravity were stronger, houses and buildings would have to be more sturdy so they do not get crushed to the ground. If gravity were weaker, buildings and houses would have to be built stronger so they do not float away.

Hope this helps you!

8 0

3 years ago

Read 2 more answers

Whose definition of acids and bases emphasizes the role of protons

torisob [31]

Answer:

Bronsted Lowry

Explanation:

Acid is defined as a proton donor.

While base is a proton acceptor

What is an acid An acid

An acid is a substance that donates protons or accepts a pair of valence electrons to form a bond

What is a base?

A base is a substance that can accept protons or donate a pair of valence electrons to form a bond. Bases can be thought of as the chemical opposite of acids.

3 0

3 years ago

Help me solve this please

Leto [7]

Since it's a projectile being launched the only force acting upon it is gravity, since the object is in free fall once it's launched

so to calculate time you'd utilize the general formula of
$xf = xi + vxi(t) + \frac{1}{2} (a) {t}^{2}$
and then solve using time and make it into the y axis, so change the x's to y's, which will change a to g.
since Vyi is always usually 0, you can drop that out of this equation so the formula to find time would be
$t = \sqrt{ \frac{2(y)}{g} }$
So you'll plug in and it'll be
$t = \sqrt{ \frac{2( - 49m)}{ - 9.81 \frac{m}{s {}^{2} } } }$
to find the maximum height you'll have to do some trigonometry to solve it.
To make it easier draw a triangle
put the 60° mark as shown in the picture.
Then you'll need to find the hypotenuse or horizontal to find the vertical
So the hypotenuse would be the 113m/s
so then you'll use
$\ \sin( 60) = ( \frac{o}{h})$

plug in the numbers
$113( \ \sin (60) ) = o$
now that you have the vertical

use the formula
${vf}^{2} = {vi}^{2} + 2gd$
solve for d which will give you the hypotenuse
$d = { (-vertical \frac{m}{s} )}^{2} \div 2( - 9.81 \frac{m}{ {s}^{2} } )$
The "vertical" is what you found in the previous step.
Vf^2 is equal to 0 so you can just drop that number out since it's 0
then once you have that then youre not done yet
since you're on a cliff of 49 m you'll have to add 49m to the previous answer that you found d to find the maximum height.

I hope this helps!

6 0

2 years ago