Kind of physical barrier

What is the acceleration of the object in the graph?

viktelen [127]

Answer:

-0.8 m/s²

Explanation:

Acceleration is the slope of a velocity vs. time graph.

a = Δv / Δt

a = (0 m/s − 12 m/s) / (15 s − 0 s)

a = -0.8 m/s²

3 0

2 years ago

A pogo stick has a spring with a force constant of 2.50 × 104 N/m , which can be compressed 11.2 cm. what maximum height, in met

AleksandrR [38]

Answer:

h = 36.4 cm

Explanation:

given,

spring constant = 2.5 x 10⁴ N/m

compressed distance = 11.2 cm = 0.112 m

mass of the child = 44 kg

maximum height = ?

by energy of conservation

$K.E_i +P.E_i= K.E_f + P.E_f$

$\dfrac{1}{2}kx^2 = mgh$

$\dfrac{1}{2}\times 2.5 \times 10^4 \times 0.112^2 = 44\times 9.8 \times h$

$156.8 = 44 \times 9.8 \times h$

$h = \dfrac{156.8}{44 \times 9.8}$

h = 0.364 m

h = 36.4 cm

7 0

2 years ago

How many turns are in its secondary coil, if its input voltage is 120 V and the primary coil has 210 turns

Tasya [4]

Complete Question

How many turns are in its secondary coil, if its input voltage is 120 V and the primary coil has 210 turns.

The output from the secondary coil is 12 V

Answer:

The value is $N_s = 21 \ turns$

Explanation:

From the equation we are told that

The input voltage is $V_{in} = 120 \ V$

The number of turns of the primary coil is $N_p = 210 \ turn$

The output from the secondary is $V_o = 12V$

From the transformer equation

$\frac{N_p}{V_{in}} =\frac{N_s}{V_o}$

Here $N_s$ is the number of turns in the secondary coil

=> $N_s = \frac{N_p}{V_{in}} * V_s$

=> $N_s = \frac{210}{120} * 12$

=> $N_s = 21 \ turns$

4 0

3 years ago

When viewing an object, we see its color according to the wavelength of light that the object A. absorbs. B. transmits. C. conta

max2010maxim [7]

D. Reflects

The object absorbs the rest of the color spectrum

7 0

2 years ago

Read 2 more answers

If a single-load Series circuit has one 20 Ohm bulb, and a

Alex Ar [27]

At the instant the second bulb is connected ...

... the brightness of the <u>first bulb</u> doesn't change

... the brightness of the <u>second bulb</u> changes from dark (no brightness) to equal to the first bulb

5 0

3 years ago