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Igoryamba
2 years ago
14

A cable raises a mass of 120.0 kg with a constant speed. What

Physics
1 answer:
myrzilka [38]2 years ago
5 0

The mass is rising with a constant speed.  

=> So it has no vertical acceleration.

=> So there is no net vertical force acting on it.

=> So the sum of the vertical forces on it is zero.

There are two vertical forces acting on the mass.

=> the force of gravity, pulling it down

=> the tension in the cable, pulling it up.

The force of gravity acting on the mass (its weight) is (mass) x (gravity).

=> That's (120 kg) x (9.8 m/s²) downward.

=> That's 1,176 newtons downward.

If the vertical forces add up to zero, the other force ... the tension in the cable ... must be the same magnitude in the opposite direction.

=> The force of tension in the cable is <em>1,176 newtons upward</em>.  

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3 years ago
I stretch a rubber band and "plunk" it to make it vibrate in its fundamental frequency. I then stretch it to twice its length an
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Answer:

The new frequency (F₂ ) will be related to the old frequency by a factor of one (1)

Explanation:

Fundamental frequency = wave velocity/2L

where;

L is the length of the stretched rubber

Wave velocity = \sqrt{\frac{T}{\frac{M}{L}}}

Frequency (F₁) = \frac{\sqrt{\frac{T}{\frac{M}{L}}}}{2*L}

To obtain the new frequency with respect to the old frequency, we consider the conditions stated in the question.

Given:

L₂ =2L₁ = 2L

T₂ = 2T₁ = 2T

(M/L)₂ = 0.5(M/L)₁ = 0.5(M/L)

F₂ = \frac{\sqrt{\frac{2T}{0.5(\frac{M}{L})}}}{4*L} = \frac{\sqrt{4(\frac{T}{\frac{M}{L}}})}{4*L} = \frac{2}{2} [\frac{\sqrt{\frac{T}{\frac{M}{L}}}}{2*L}] = F_1

Therefore, the new frequency (F₂ ) will be related to the old frequency by a factor of one (1).

7 0
3 years ago
Which of the following is an example of sound energy
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3 years ago
Lifting a box off the floor is an example of what type of force?
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8 0
3 years ago
Read 2 more answers
Giving brainliest!! if you answer correctly :) (30pts)
myrzilka [38]

Answer:

mass = 4kg

Explanation:

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KE = 50

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8 0
2 years ago
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