Answer:
P.E = 0.068 J = 68 mJ
Explanation:
First we need to find the height attained by the ball toy. For this purpose, we will be using 3rd equation of motion:
2gh = Vf² - Vi²
where,
g = -9.8 m/s² (negative sign due to upward motion)
h = height attained by the ball toy = ?
Vf = Final Velocity = 0 m/s (since it momentarily stops at the highest point)
Vi = Initial Velocity = 3 m/s
Therefore,
2(-9.8 m/s²)h = (0 m/s)² - (3 m/s)²
h = (9 m²/s²)/(19.6 m/s²)
h = 0.46 m
Now, the gravitational potential energy of ball at its peak is given by the following formula:
P.E = mgh
P.E = (0.015 kg)(9.8 m/s²)(0.46 m)
<u>P.E = 0.068 J = 68 mJ</u>
Milky Way Galaxy, same one as you.
media.discordapp.net/attachments/782414373888458783/826224189828366377/video0.mp4
Answer:
600 and 1500 [ohm
Explanation:
To solve this problem we must use ohm's law, which tells us that the voltage is the product of the current by the resistance, so we have:
V = I*R
where:
V = voltage [V]
I = current [amp]
R = resistance [ohm]
<u>Therefore:</u>
R = V/I
R1 = 60/(40*10^-3) = 1500 [ohm]
R2 = 60/(100*10^-3) = 600 [ohm]
So the resistance should be among 600 and 1500 [ohm]
