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taurus [48]
4 years ago
10

You did 200 joules of work lifting a 150-newton backpack. How high did you lift the backpack?

Physics
1 answer:
kaheart [24]4 years ago
8 0
We know that:
W=Fs
200J=150N*s
s=200J/150N
s=1,33m
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a water line starts the service with an altitude of 1200m over the sea level, what is the velocity of the water above 1050 m ove
Ilia_Sergeevich [38]

Answer:

Velocity = 94.85m/s

Explanation:

<u>Given the following data ;</u>

Height = 1200m

Vertical distance = 1050m

To find the time, we would use the second equation of motion;

S = ut + \frac {1}{2}at^{2}

Substituting into the equation, we have;

1200 = 0(t) + \frac {1}{2}*9.8*t^{2}

1200 = 0 + 4.9*t^{2}

1200 = 4.9*t^{2}

t^{2} = \frac {1200}{4.9}

t = \sqrt{122.45}

t = 11.07 secs

To find the velocity;

Mathematically, velocity is given by the equation;

Velocity = \frac{distance}{time}

Substituting into the above equation;

Velocity = \frac{1050}{11.07}

Velocity = 94.85m/s

Therefore, the velocity of the water above 1050 m over the sea level is 94.85m/s.

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3 years ago
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What does it mean to say that the protons give the atom is identity
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Y_Kistochka [10]

Answer:

Average speed is 60 km/hour

Explanation:

When we need to calculate average speed, we use this equation:

V = \frac{x_{f} - x_{o}}{t_{f} - t_{o}}

Where:   x_{o} = 0 km   position at the beginning

              x_{f} = 240 km   at the end

              t_{o} = 0 hours

              t_{f} = 4 hours

Then:     V = \frac{240 km - 0 km}{4 hours - 0 hours}

              V = \frac{240 km}{4 hours}

Finally    V = 60 km/hour

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