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Igoryamba
3 years ago
9

DIRECTIONS: Use this information to answer Parts A, B, and C.

Mathematics
1 answer:
Talja [164]3 years ago
3 0

Answer:

V=706.85

Step-by-step explanation:

Well, first of when you want to find the volume of the cone you need to have a radius and hieght. And the radius is half the diameter, so divide the diameter into half: 10/2=5 in. and you already have the height so just plug in the numbers.

Formula: V= \frac{1}{3}\pir^{2}h ---> V= \frac{1}{3}\pi(5^{2})(27)

And put the plugged in formula in your calculator and you'll find the answer!

V=706.85

I hope this helped.

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5/21 Marks
cricket20 [7]

Answer:

large jar

Step-by-step explanation:

large jar= £1.54 (divide) 440= 0.0035

small jar= £1.26 (divide) 340= 0.0037

as the large jar cost less (0.0035 > 0.0037) the large jar is the best value for money

8 0
4 years ago
A snake slithers 2/9 miles in 4/5 hours what is its speed in miles per hour
Mamont248 [21]

Answer:

5/18

Step-by-step explanation:

speed = distance / time

s = (2/9 miles) / (4/5 hours)

To divide by a fraction, multiply by the reciprocal:

s = (2/9) × (5/4)

s = 10/36

s = 5/18

So the snake's speed is 5/18 miles per hour.

3 0
3 years ago
Which of the following are polynomials?<br><br> PLS HELP
Arturiano [62]

Answer:

option (B) I'm certain of.

but if you are required to choose more than one then option (B) and (C) since polynomials are coefficients with power 2.

Step-by-step explanation:

Hope this helps.

Good luck.

4 0
2 years ago
Members of a high school club sold hamburgers at a baseball game to raise money. They sold 278 hamburgers. If the buns come in p
Mariulka [41]
The answer, at least what I got, is 17.375 . They'd have to open an eighteenth package because the extra .375 is not in the original package, so I would go with B . 
5 0
4 years ago
Read 2 more answers
What is the solution to the following inequality?<br> -82 ≤ 5v + 3
olga nikolaevna [1]

Answer:

v ≥ -17

Step-by-step explanation:

-82 ≤ 5v + 3

-82 - 3 ≤ 5v

5v ≥ -85

v ≥ -17

3 0
3 years ago
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