Solution:
initial sphere mvr = final sphere mvr + Iω
where I = mL²/3 = 2.3g * (2m)² / 3 = 3.07 kg·m²
0.25kg * (12.5 + 9.5)m/s * (4/5)2m = 3.07 kg·m² * ω
where: ω = 2.87 rad/s
So for the rod, initial E = KE = ½Iω² = ½ * 3.07kg·m² * (2.87rad/s)²
E = 12.64 J becomes PE = mgh, so
12.64 J = 2.3 kg * 9.8m/s² * h
h = 0.29 m
h = L(1 - cosΘ) → where here L is the distance to the CM
0.03m = 1m(1 - cosΘ) = 1m - 1m*cosΘ
Θ = arccos((1-0.29)/1) = 44.77 º
21.75 Miles Per Hour
I got this by multiplying 7.25(3) because I know 20 minutes is 1/3 of 1 he
Answer:
D
Explanation:
by having different ethnic groups
Answer:
the force remains constant if the charge does not change
Explanation:
In a capacitor the capacitance is given by
C = ε₀ A / d
Where ε₀ is the permissiveness of emptiness, A is about the plates and d the distance between them.
The charge on the capacitor is given by the ratio
Q = C ΔV
Let's apply these expressions to our problem, if the load remains constant
C = Q / ΔV = ε₀ A / d
ΔV / d = Q / ε₀ A
If the distance increases the capacitance should decrease, therefore if the charge is a constant the voltaje difference must increase
Now we can analyze the force on the test charge in the center of the capacitor
ΔV = E d
E= ΔV/d
F = q E
F = q ΔV / d
Let's replace
F = q Q /ε₀ A
From this expression we see that the force is constant since the voltage increase is compensated by increasing the distance, therefore the correct answer is that the force remains constant if the charge does not change
