Answer:
Explanation:
Law of conservation of momentum is applied in solving collision problem. When two body collides, their momentum after collision can be determined using the law.
The law States that the sum of momentum of two bodies before collision is equal to the sum of their momentum after collision. Before collision, both bodies moves with a different velocity while during some cases, the bodies moves with a common velocity after collision.
Whether they move with or without the same velocity depends on the type of collision that exists between them after the collision. After collision, some object sticks together and move with a common velocity while some doesn't.
If the bodies sticks together after collision, the type of collision that occur is inelastic (energy is not conserved) and if they splits after collision, the type of collision that occur is an elastic collision (energy is conserved).
Let m1 and m2 be the masses of the bodies
u1 and u2 be their velocities before collision
v1 and v2 be their velocities after collision.
According to the law;
m1u1 + m2u2 = m1v1 + m2v2
Note that momentum = mass × velocity of the body.
This is what I got:
Net force in the Y direction:
ΣFy = T1 - T2
F = ma
ma = T1 - T2
Isolate for T2
ma - T1 = -T2
Multiply by -1
T1 - ma = T2
100 - (3)(2) = T2
100 - 6 = T2
T2 = 94 N
Answer:
31.831 Hz.
Explanation:
<u>Given:</u>
The vertical displacement of a wave is given in generalized form as
<em>where</em>,
- A = amplitude of the displacement of the wave.
- k = wave number of the wave =
= wavelength of the wave.- x = horizontal displacement of the wave.
= angular frequency of the wave = 
.- f = frequency of the wave.
- t = time at which the displacement is calculated.
On comparing the generalized equation with the given equation of the displacement of the wave, we get,
therefore,
It is the required frequency of the wave.
