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Sliva [168]
3 years ago
5

A number cube has 6 different faces, numbered 1 to 6. All faces have an equal probability of being rolled. What is the probabili

ty of rolling a 5?
please no links!!​
Mathematics
1 answer:
Nataly_w [17]3 years ago
8 0

Answer:

its a 1/6 chance

Step-by-step explanation:

each face has a 1/6 chance of being rolled since there are 6 faces

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Please solve im gonna fail
BARSIC [14]

Answer:

144

Step-by-step explanation:

area of square is 132 + area of 2 triangles = 12 then add

6 0
2 years ago
Is a trapezoid always a quadrilateral?
Alona [7]

Answer:

Since a quadrilateral is a shape with four sides, yes it will be a quadrilateral.

Step-by-step explanation:

7 0
3 years ago
Jalil is training for a marathon. On Monday, he biked 7.2 miles from his home to a park where he ran 10 laps on a path around a
GuDViN [60]

Answer:

.25 or 1/4 mile

Step-by-step explanation:

7.2 miles biking x 2 (round trip)= 14.4 miles

Total miles is 16.9-14.4= 2.5 miles left to run 10 times around a small pond. So to find out the distance of each lap around the pool you divide 2.5 miles by 10 laps equals .25 or 1/4 Mike is the distance around the pond.

5 0
3 years ago
A force of 3 pounds is required to hold a spring stretched 0.6 feet beyond its natural length. how much work (in foot-pounds) is
ioda

The work done (in foot-pounds) in stretching the spring from its natural length to 0.7 feet beyond its natural length is 1.23 foot-pound

<h3>Data obtained from the question</h3>

From the question given above, the following data were obtained:

  • Force (F) = 3 pounds
  • Extension (e) = 0.6 feet
  • Work done (Wd) =?

<h3>How to determine the spring constant</h3>
  • Force (F) = 3 pounds
  • Extension (e) = 0.6 feet
  • Spring constant (K) =?

F = Ke

Divide both sides by e

K = F/ e

K = 3 / 0.6

K = 5 pound/foot

Thus, the spring constant of the spring is 5 pound/foot

<h3>How to determine the work done</h3>
  • Spring constant (K) = 5 pound/foot
  • Extention (e) = 0.7 feet
  • Work done (Wd) =?

Wd = ½Ke²

Wd = ½ × 5 × 0.7²

Wd = 2.5 × 0.49

Wd = 1.23 foot-pound

Therefore, the work done in stretching the spring 0.7 feet is 1.23 foot-pound

Learn more about spring constant:

brainly.com/question/9199238

#SPJ1

5 0
2 years ago
Simplify.<br> 27²= <br> FAST plsssssssssssssssssssssss
sdas [7]

Answer:

729

Step-by-step explanation:

27²=  (27)(27)=729

8 0
3 years ago
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