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Vikentia [17]
3 years ago
7

An oil tank has to be drained for maintenance. The tank is shaped like a cylinder that is 4 ft long with a diameter of 2.2 ft. S

uppose oil is drained at a
rate of 1.5 per minute. If the tank starts completely full, how many minutes will it take to empty the tank?
Use the value 3.14 for, and round your answer to the nearest minute. Do not round any intermediate computations.
Mathematics
1 answer:
gavmur [86]3 years ago
8 0

Answer:

8\:\mathrm{minutes}

Step-by-step explanation:

The volume of a cylinder is given as:

r^2\cdot\pi\cdot h

Since the diameter is 2.2, the radius is \frac{2.2}{2}=1.1.

Therefore, the volume of this cylinder is:

1.1^2\cdot 3.14\cdot 4=15.1976\:\mathrm{ft^3}, using \pi=3.14 as requested in the problem.

Since the tank is emptied at a constant rate of 1.5\:\mathrm{ft^3\:per\:minute}, it will take

\frac{15.1976}{1.5}=7.5988=\fbox{$8\:\mathrm{minutes}$} to empty the tank.

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Answer:

A = 7 x 9.3

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3 years ago
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Elza [17]
Part A

Answer: The common ratio is -2

-----------------------------------

Explanation: 

To get the common ratio r, we divide any term by the previous one

One example:
r = common ratio
r = (second term)/(first term)
r = (-2)/(1)
r = -2

Another example:
r = common ratio
r = (third term)/(second term)
r = (4)/(-2)
r = -2
and we get the same common ratio every time

Side Note: each term is multiplied by -2 to get the next term

============================================================
Part B

Answer:
The rule for the sequence is 
a(n) = (-2)^(n-1)
where n starts at n = 1

-----------------------------------

Explanation:

Recall that any geometric sequence has the nth term
a(n) = a*(r)^(n-1)
where the 'a' on the right side is the first term and r is the common ratio

The first term given to use is a = 1 and the common ratio found in part A above was r = -2
So,
a(n) = a*(r)^(n-1)
a(n) = 1*(-2)^(n-1)
a(n) = (-2)^(n-1)

============================================================
Part C

Answer: The next three terms are 16, -32, 64

-----------------------------------

Explanation:

We can simply multiply each previous term by -2 to get the next term. Do this three times to generate the next three terms

-8*(-2) = 16
16*(-2) = -32
-32*(-2) = 64

showing that the next three terms are 16, -32, and 64

An alternative is to use the formula found in part B

Plug in n = 5 to find the fifth term
a(n) = (-2)^(n-1)
a(5) = (-2)^(5-1)
a(5) = (-2)^(4)
a(5) = 16 .... which matches with what we got earlier

Then plug in n = 6
a(n) = (-2)^(n-1)
a(6) = (-2)^(6-1)
a(6) = (-2)^(5)
a(6) = -32 .... which matches with what we got earlier

Then plug in n = 7
a(n) = (-2)^(n-1)
a(7) = (-2)^(7-1)
a(7) = (-2)^(6)
a(7) = 64 .... which matches with what we got earlier

while the second method takes a bit more work, its handy for when you want to find terms beyond the given sequence (eg: the 28th term)
6 0
3 years ago
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