Answer:
- digits used once: 12
- repeated digits: 128
Step-by-step explanation:
In order for a number to be divisible by 4, its last two digits must be divisible by 4. This will be the case if either of these conditions holds:
- the ones digit is an even multiple of 2, and the tens digit is even
- the ones digit is an odd multiple of 2, and the tens digit is odd.
We must count the ways these conditions can be met with the given digits.
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Since we only have even numbers to work with, the ones digit must be an even multiple of 2: 4 or 8. (The tens digit cannot be odd.) The digits 4 and 8 comprise half of the available digits, so half of all possible numbers made from these digits will be divisible by 4.
<h3>digits used once</h3>
If the numbers must use each digit exactly once, there will be 4! = 24 of them. 24/2 = 12 of these 4-digit numbers will be divisible by 4.
<h3>repeated digits</h3>
Each of the four digits can have any of four values, so there will be 4^4 = 256 possible 4-digit numbers. Of these, 256/2 = 128 will be divisible by 4.
Change each mixed fraction to improper
3 2/5 = 15/5 + 2/5 = 17/5
9 1/10 = 90/10 + 1/10 = 91/10
Find a common denominator. Multiply 2 to both numerator and denominator of 17/5
17/5(2/2) = 34/10
34/10 + 91/10 = 125/10
125/10
Simplify. Divide
125/10 = 12.5
12.5 is your answer
hope this helps
Answer:
Given equation have two solutions.
x = 
Right option is (D)
Step-by-step explanation:
We have given,
we can rewrite this equation in the form given as:
6x² + 40 + 31x = 0
or 6x² + 31x + 40 = 0
On solving this quadratic equation, we get :
x =
That means, given equation have two solutions.
Right option is (D)
How to solve it:
•1. multiply 7 x 1= 7
•2. multiply 7 x 4k= 28k
so the answer is: 7+28k
i hope i have been helpful :)
Answer:
Step-by-step explanation:
The sine of an angle is equal to the cosine of its complement, and vice versa.
sin ∠QOP = cos ∠ROQ
cos ∠ROQ = sin ∠QOP
