There are 6.022 × 10²³ atoms in 39.948 g of argon and 4.0026 g of helium.
Explanation:
39.945 g/mole is the molar mass of argon so 39.948 g of argon are equal to 1 mole of argon.
4.0026 g/mole is the molar mass of helium so 4.0026 g of helium are equal to 1 mole of helium.
We know that Avogadro's number tell us the number of particles in 1 mole of substance which is 6.022 × 10²³.
So in 39.948 g of argon and 4.0026 g of helium contains the same number of atoms, 6.022 × 10²³.
Learn more about:
Avogadro's number
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When you know the number of moles in either the reactant or product and also when the compounds involved are either basic or acidic
Molecular mass of Zn = 65.38
<span>1 mol = 65 g </span>
<span>0.2 mol of Zinc = 13.076 g of Zinc </span>
<span>13.076 g of Zinc is completely converted in air to ZnO </span><span>in one month
= 13.076 g / 30 days = 0.435 g per day
</span>
<span>The rate of conversion of the zinc = 0.44 g / day</span>
