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Vikentia [17]
3 years ago
8

The net force on a vehicle that is accelerating at a rate of 1.5 m/s2 is 1,800 newton's. What is the mass of the vehicle to the

nearest kilogram?​
Chemistry
1 answer:
levacccp [35]3 years ago
3 0

Answer:

<h2>1200 kg</h2>

Explanation:

The mass of the vehicle can be found by using the formula

m =  \frac{f}{a}  \\

f is the force

a is the acceleration

From the question we have

m =  \frac{1800}{1.5}  \\

We have the final answer as

<h3>1200 kg</h3>

Hope this helps you

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Calculate the amount of heat released in the combustion of 10.5 grams of Al with 3 grams of O2 to form Al2O3(s) at 25°C and 1 at
ElenaW [278]

Answer : The amount of heat released in the combustion is, 209.5 kJ

Explanation :

First we have to calculate the moles of Al and O_2.

\text{ Moles of }Al=\frac{\text{ Mass of }Al}{\text{ Molar mass of }Al}=\frac{10.5g}{27g/mole}=0.389moles

\text{ Moles of }O_2=\frac{\text{ Mass of }O_2}{\text{ Molar mass of }O_2}=\frac{3g}{32g/mole}=0.188moles

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction will be:

4Al+3O_2\rightarrow 2Al_2O_3

From the balanced reaction we conclude that

As, 3 mole of O_2 react with 4 mole of Al

So, 0.188 moles of O_2 react with \frac{4}{3}\times 0.188=0.251 moles of Al

From this we conclude that, Al is an excess reagent because the given moles are greater than the required moles and O_2 is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of Al_2O_3

From the reaction, we conclude that

As, 3 mole of O_2 react to give 2 mole of Al_2O_3

So, 0.188 moles of O_2 react to give \frac{2}{3}\times 0.188=0.125 moles of Al_2O_3

Now we have to calculate the amount of heat released in the combustion.

As, 1 mole of Al_2O_3 releases amount of heat = 1676 kJ

So, 0.125 mole of Al_2O_3 releases amount of heat = 0.125\times 1676kJ=209.5kJ

Thus, the amount of heat released in the combustion is, 209.5 kJ

4 0
3 years ago
For the chemical reaction , I identify the reactant and the products .
svetlana [45]

The reactant is Mercury (II) Oxide while the products are Mercury and Oxygen separately.

This is because the reactants are typically always on the left side of the yields symbol. In this decomposition reaction, it would still be the same as at the end of the reaction, there were to products produced: Mercury and Oxygen.

Products tend to always be on the right side of the yields symbol, they're what comes out of a reaction no matter what type.

Hope this helps!

7 0
4 years ago
Which unstable element is used to determine the age of volcanic rock?
77julia77 [94]

<em><u>Answer:</u></em>

Potassium.

<u><em>Explanation:</em></u>

Therefore, the answer is Potassium. You might think, that because we were talking about Argon as well, the answer is both of them, but no. Everything starts with Potassium but it decays into Argon during the process.

6 0
3 years ago
Read 2 more answers
6 Li + Zn3(PO4)2 ------- &gt; 2 Li3PO4 + 3 Zn
bogdanovich [222]

Moles of Lithium phosphate : 0.495

<h3>Further explanation</h3>

Given

6 Li + Zn₃(PO₄)₂ ------- > 2 Li₃PO₄ + 3 Zn

Required

Moles of Lithium phosphate

Solution

moles of Zinc(Ar=65,38 g/mol) :

= mass : Ar

= 48.6 : 65.38

= 0.743

From equation, mol ratio of Zn :  Li₃PO₄ = 3 : 2, so mol  Li₃PO₄ :

= 2/3 x mol Zn

= 2/3 x 0.743

= 0.495

3 0
3 years ago
how many moles of sodium hydroxide (NaOH) are required to completely neutralize 2 mol of nitric acid (HNO3)
Brut [27]

2 moles of sodium hydroxide will be needed.

<h3><u>Explanation</u>:</h3>

Sodium hydroxide is a compound which is a base and nitric acid is the acid. The formula of the nitric acid is HNO3 and that of sodium hydroxide is NaOH.

The reaction between them are

NaOH +HNO3 =NaNO3 +H2O.

So here we can see that 1 mole of sodium hydroxide reacts with 1 mole of nitric acid to produce 1 mole of sodium nitrate and 1 mole of water.

So for 2 moles of nitric acid, 2 moles of sodium hydroxide will be required.

6 0
4 years ago
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