Answer:
6.022×10²² molecules
Explanation:
Given data:
Volume of nitrogen = 224 L
Pressure = standard = 1 atm
Temperature = standard = 273 K
Number of molecules = ?
Solution:
PV = nRT
1 atm × 224 L = n × 0.0821 atm.L/mol.K × 273 K
224 atm.L = n ×22.41 atm.L/mol
n = 224 atm.L/22.41 atm.L/mol
n = 10 mol
1 mole contain 6.022×10²³ molecules
10 mol×6.022×10²³ molecules/ 1 mol
60.22×10²³ molecules
6.022×10²² molecules
Answer:
you sound like a cool guy, ill email ya one of these days
Explanation:
Answer:
The molarity of the formed CaBr2 solution is 0.48 M
Explanation:
Step 1: Data given
Number of moles CaBr2 = 0.72 moles
Volume of water = 1.50 L
Step 2: Calculate the molarity of the solution
Molarity of CaBr2 solution = moles CaBr2 / volume water
Molarity of CaBr2 solution = 0.72 moles / 1.50 L
Molarity of CaBr2 solution = 0.48 mol / = 0.48 M
The molarity of the formed CaBr2 solution is 0.48 M
Answer:
The volume occupied by 2.34 grams of CO2 gas at STP is 1.18 L
Answer:
68.6 m
Explanation:
Speed is defined as distance covered per unit time and expressed as
S=d/t
Where d is distance and t is speed.
Making d the subject of the above formula then
d=st
Substituting 343 m/s dor s and 0.200 s for s then
d=343*0.2=68.6 m
Therefore, the distance is 68.6 m
