Answer:
pH = 7.46.
Explanation:
- The ionization of water is given by the equation :
<em>H₂O(l) ⇄ H⁺(aq) + OH⁻(aq),</em>
<em></em>
- The equilibrium constant (Kw) expression is:
<em>Kw = [H⁺][OH⁻] = 0.12 x 10⁻¹⁴. </em>
<em></em>
in pure water and neutral aqueous solution, [H⁺] = [OH⁻]
So, Kw = [H⁺]²
∴ 0.12 x 10⁻¹⁴ = [H⁺]²
∴ [H⁺] = 3.4 x 10⁻⁸ M.
∵ pH = - log [H⁺]
pH = - log (3.4 x 10⁻⁸) = 7.46.
Here are your answers:
1. MgBr2 + Cl2 = MgCl2 + Br2
Balancing,
Already balanced.
Type of reaction: single displacement
2. Al + Fe2O3 = Al2O3 + Fe
Balancing,
2Al + Fe2O3 = Al2O3 + 2Fe
Type: single displacement reaction
3. AgNO3 + ZnCl2 = AgCl + N2O6Zn
Balancing,
2AgNO3 + ZnCl2 = 2AgCl + N2O6Zn
Type: double displacement reaction
MnO2
4. H2O2 ====== O2 + H20 [being catalyzed by manganese dioxide]
Balancing,
MnO2
2H2O2 ====== O2 + 2H2O
Type: decomposition reaction
5. Zn + HCl = ZnCl2 + H2
Balancing,
Zn + 2HCl = ZnCl2 + H2
Type: single displacement reaction
6. H2SO4 + NaOH = Na2SO4 + H2O
Balancing,
H2SO4 + 2NaOH = Na2SO4 + 2H2O
Type: Acid-base reaction
That took hella long!!! Hope it helps.
This depends in what type reaction is occurring. It may be an endothermic reaction or an exothermic reaction. If the reaction is endothermic or heat is being absorbed by the reaction, then the forward reaction is favored or the products are being formed by the addition of heat. If the reaction is exothermic or heat is released by the reaction, then the backward reaction is favored or the reactants are being formed by the addition of heat.
Answer:
Two
Explanation:
I believe your unbalanced equation should be
H₂O₂ + I₂ ⟶ IO₃⁻
The half-reactions and the overall reaction are:
5 × [H₂O₂ + 2H⁺ +2e⁻ ⟶ 2H₂O]
1 × <u>[ I₂ + 6H₂O ⟶ 2IO₃⁻ + 12H⁺ + 10e⁻]
</u>
5H₂O₂ + I₂ ⟶ 2IO₃⁻ + 2H⁺ + 4H₂O
The reaction needs two hydrogen ions for balancing.
