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2 years ago

HELP ME FOR LOVE OF GOD THIS HOME WORK IS GIVING ME BRAINWAVES

Mathematics

1 answer:

Ierofanga [76]2 years ago

5 0

The answer is A, the flat rate is the y-intercept and hourly is the slope

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PLEase Help ME In This Work!!

tigry1 [53]

Answer:

y=2x

Step-by-step explanation:

it is a proportional relationship and the slope is 2

8 0

2 years ago

1. Students who attended a track and field meet were polled, and 75% of them said that track and field meets are more fun to att

IRINA_888 [86]

Answer:

Part 1: It is not a valid conclusion to say that track and field sports are more popular than soccer based on the survey. The survey was taken at a track and field event so the people that were surveyed are probably biased.

Part 2: A better way of determining which sport is more popular is by counting how many people show up to each event and comparing the results.

6 0

2 years ago

What is y + 9 < -6 ???

FrozenT [24]

Y is less than or equal to -16 i think but I’m not sure

4 0

2 years ago

Use gcf distributive property to find the sum of 28 and 80.

Anna71 [15]

Step-by-step explanation:

The GCF of 28 and 80 is 4.

<u>Distribute 4 for 28 and 80, then solve:</u>

$4(7) + 4(20) = 28 + 80$

$4(7 + 20) = 28 + 80$

$4(27) = 28 + 80$

$108 = 80 + 28$

7 0

2 years ago

If the area of a baseball diamond (shape of a square) is 8100 ft squared, how would you find the distance from 1st base to 3rd b

Readme [11.4K]

Answer:

Exact distance = $90\sqrt{2}$ feet
Approximate distance = 127.2792 feet.

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Explanation:

The area of the square is 8100 square feet, abbreviated ft^2.

Apply the square root to find the distance from any base to its adjacent counterpart (eg: from 1st to 2nd base). So we get sqrt(8100) = 90 ft as that side distance. Notice that 90*90 = 8100.

If you were to draw a line from 1st base to 3rd base, then you would split the square into two congruent right triangles. Each right triangle is isosceles (the two legs being 90 ft each).

Use the pythagorean theorem to find the hypotenuse.

$a^2 + b^2 = c^2\\\\c = \sqrt{a^2+b^2}\\\\c = \sqrt{90^2+90^2}\\\\c = \sqrt{2*90^2}\\\\c = \sqrt{2}*\sqrt{90^2}\\\\c = \sqrt{2}*90\\\\c = 90\sqrt{2} \ \text{ ... exact distance}\\\\c \approx 127.2792 \ \text{ ... approximate distance}\\\\$

The distance from 1st to 3rd base is roughly 127.2792 feet.

5 0

2 years ago