Answer: Option (C) is the correct answer.
Explanation:
As we know that metals are able to conduct electricity so, when a negatively charges rod is kept closer to the left sphere then electrons will enter the sphere.
Since, like charges repel each other. Hence, some of the negative changes from the rod will repel the negative charges of left sphere.
As both left and right spheres are touching each other so, the electrons will move towards the right sphere. As a result, there will be too many electrons (negative charge) present on the right sphere and very less electrons present in the left sphere.
Thus, we can conclude that the statement right sphere is negatively charged, another is charged positively, is true.
Answer:
The moist air mass would be denser
Explanation:
Density is defined as mass per unit volume. Hence the density of a substance (solid, liquid or gas) is directly proportional to its mass and inversely proportional to the volume occupied.
The mass of a gas is the product of its number of moles and its molar mass (mass = number of moles × molar mass), which indicates that the mass is directly proportional to molar mass, so the higher the molar mass, the higher the mass of different gases at equal volumes, temperature and pressure.
From the information given, the molar weight of dry air = 29g/mole.
The molar weight of moist air = molar weight of dry air + molar weight of water vapour = 29 + 18 = 47g/mole.
Therefore since higher molar mass transits to higher mass, it can be said that moist air of molar mass 47g/mole is denser than dry air of molar mass 29g/mole at equal volume, temperature and pressure.
Simple picture the two gasses in two transparent jars, the heavier gas (moist air) settles more at the bottom of the jar, and has less random motion hence is more compressed and denser, than dry air that has more freedom to move randomly because of its lesser weight.
Physical changes are temporary, such as an ice cube melting and chemical changes are more permanent, such as acid rain weathering off the side of a rock.
Answer:
B) Its horizontal velocity component is the same as it was just as it was launched
Explanation:
From dynamic we know that free falling objects had two components of velocity
The only acceleration that takes place in this case is gravity in the y-component of velocity

Since a=0 and
that means that the velocity at the y-component changes with time but the horizontal component remain the same
This means that the horizontal velocity is not 0 but is <u><em>the same as it was just as it was launched</em></u>