BPC is an isosceles triangle so the base angles are equal.
x is 30
Answer:
11.31 ft
Step-by-step explanation:
Here in this problem ladder forms a right triangle with the wall of the house and it is acts as hypotenuse, length of one leg of right triangle given to be 4 feet.
Let the ladder reaches x ft height of the house.
Hence, by Pythagoras theorem:
Hence, the ladder reaches 11.31 ft height of the house.
Answer:
The answer for Factorization is (x+6)(x-2) = 0 or Solving for x is 2 and -6.
Step-by-step explanation:
x² - 12 = -4x
Factorisation :
x² + 4x - 12 = 0
x² - 2x + 6x - 12 = 0
x(x-2)x + 6(x-2) = 0
(x+6)(x-2) = 0
Solve for x :
(x+6)(x-2) = 0
x + 6 = 0
x = -6
x - 2 = 0
x = 2
Let G be some point on the diagonal line away from point E.
Angle DEG represents angle 1.
We're given that angle DEF is a right angle which means it's 90 degrees. Angle DEG is some angle smaller than 90 degrees. By definition, that must mean angle 1 is acute. Any acute angle is smaller than 90 degrees. There's not much else to say other than this is just a definition problem.
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Extra side notes:
If angle 1 was a right angle, then that would mean angle GEF would have to be 0 degrees; however the diagram shows this isn't the case.
If angle 1 was obtuse, then there's no way we'd be able to fit it into angle DEF. In other words, there's no way to have an angle larger than 90 fit in a 90 degree angle.
First move the 4y to the right and the 1 to the left:
4y=5x-1
Then divide everything by 4:
y=5/4 x - 1/4
