This problem uses the relationships among current 
I, current density 
J, and drift speed 
vd. We are given the total of electrons that pass through the wire in 
t = 3s and the area 
A, so we use the following equation to to find 
vd, from 
J and the known electron density 
n,
 so: 

<span>The current
 I is any motion of charge from one region to another, so this is given by:
</span>

The magnitude of the current density is:

Being:

<span>
Finally, for the drift velocity magnitude vd, we find:
</span>
 Notice: The current I is very high for this wire. The given values of the variables are a little bit odd
Notice: The current I is very high for this wire. The given values of the variables are a little bit odd
 
        
        
        
Answer:
5 hours
step-by-step explanation:
very simple just divide 1,000 and 200 to get 5
        
             
        
        
        
Answer:
The lights bounces from the object behind which hit one's eyes. The glass is transparent because it does not absorb any radiation