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kiruha [24]
3 years ago
7

What is the difference between a light wave and an infrared wave?

Physics
2 answers:
Dmitriy789 [7]3 years ago
6 0

Answer:Infrared light has a wavelength that is longer than that of standard red light, and although considered part of the red color spectrum, infrared wavelengths are still much shorter

BlackZzzverrR [31]3 years ago
4 0
Infrared light has a wavelength that is longer than that of standard red light, and although considered part of the red color spectrum, infrared wavelengths are still much shorter than, for example, radio waves. Infra-red waves occur in the range from 1,000nm to a millimeter in length.
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a battery is tested and it is found that the voltage Vout = 1.64V with the switch open and 1.63V with the switch closed. Find th
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Rate brainliest please. Thank you

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3 years ago
A house is losing heat at a rate of 1600 kJ/h per °C temperature difference between the indoor and the outdoor temperatures. Exp
Setler [38]

Answer:

1600 kJ/h per K, 888.88 kJ/h per °F and 888.88kJ/h per R

Explanation:

We make use of relations between temperature scales with respect to degrees celsius:

1 K= 1^{\circ}C+273\\1^{\circ}F= (1^{\circ}C*1.8)+32\\1 R= (1^{\circ}C*1.8)+491.67

This means that a change in one degree celsius is equivalent to a change of one kelvin, while for a degree farenheit and rankine this is equivalent to a change of 1.8 on both scales.

So:

\frac{Q}{\Delta T(K)}=\frac{Q}{\Delta T(^\circ C)}=1600 \frac{kJ}{h} per K\\\frac{Q}{\Delta T(^\circ F)}=\frac{Q}{\Delta T(^\circ C*1.8)}=888.88 \frac{kJ}{h} per ^\circ F\\\frac{Q}{\Delta T(R)}=\frac{Q}{\Delta T(^\circ C*1.8)}=888.88 \frac{kJ}{h} per R

5 0
3 years ago
Elizabeth notices that the temperature is dropping. What piece of lab equipment should she use to measure the change in temperat
bixtya [17]

Answer:

thermometer

Explanation:

the thermometer measures temp.

4 0
3 years ago
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The buoyant force acts in all directions. Please select the best answer from the choices provided T F
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How the choice of building materials and techniques can help them cool down faster, after heating up.
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Answer:

The choice of building materials and techniques can help them cool down faster, after heating up is explained below in brief details.

Explanation:

Building materials

Buildings that are composed of rock, bricks, or pavement, or inserted into the territory, can seem cooler thanks to the great "thermal mass" of these elements – that is, their capability to assimilate and discharge heat gently, thereby softening temperatures over time, producing daytime cooler and night-time warmer.

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3 years ago
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