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Nitella [24]
1 year ago
12

the asthenosphere is an important layer because it . 5) a) responds to forces by flowing as it is relatively strong b) responds

to forces by staying rigid as it is relatively strong c) responds to forces by flowing as it is relatively weak d) responds to forces by staying rigid as it is relatively weak
Physics
1 answer:
olga nikolaevna [1]1 year ago
4 0

The asthenosphere is an important layer because it <u>responds to forces </u><u>by flowing as it is relatively weak.</u>

This is because the asthenosphere is solid, but mobile, meanwhile the lithosphere is solid and relatively rigid.

<h3 /><h3>What is asthenosphere?</h3>

The Earth's upper mantle contains an area known as the asthenosphere, which is ductile and mechanically fragile. Between 80 and 200 km (50 and 120 mi) below the surface, it is located beneath the lithosphere, and it can reach a depth of 700 km (430 mi). It is difficult to determine the asthenosphere's lower border, though.

Despite the asthenosphere being almost completely solid, its mechanical weakness is caused by a tiny quantity of rock melting (less than 0.1% of the rock). This is the primary source of magma on Earth because as it wells higher, more extensive decompression melting of the asthenosphere occurs.

It is where some magmas that erupted above subduction zones or in areas of continental rifting, as well as mid-ocean ridge basalt (MORB), originated.

Learn more about asthenosphere

brainly.com/question/6500268

#SPJ4

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Review. An electron moves in a circular path perpendicular to a constant magnetic field of magnitude 1.00 mT . The angular momen
Ghella [55]

The speed of an electron when it moves in a circular path perpendicular to a constant magnetic field is 8.88 x 10^7 m/s.

The angular momentum(L) of an electron moving in a circular path is given by the formula,

L = mvr ........(i)

We know that the radius of the path of an electron in a magnetic field is

r = mv/qB

Putting this value in equation (i),

L = mv x mv/qB

or L = (mv)^2/qB

Putting the given values in the above equation,

4 x 10^-25 = (9.1x10^-31)^2 x v^2/ 1.6 x 10^-19 x 1 x 10^-3

v comes out to be 8.88 x 10^7 m/s.

Hence, the speed of an electron when it moves in a circular path perpendicular to a constant magnetic field is 8.88 x 10^7 m/s.

To know more about "angular momentum", refer to the following link:

brainly.com/question/15104254?referrer=searchResults

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5 0
1 year ago
Which of the following is considered an energy source and a building block for the human body?
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7 0
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A gravitational _____ exists between you and every object in the universe.
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A pair of equal gravitational forces ... one in each direction ...
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4 0
3 years ago
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You drop a pencil from your desk, which is 1 meter above the floor. How long does it take for the pencil to hit the floor? How f
vova2212 [387]

Answer:

1. 0.45 s.

2. 4.41 m/s

Explanation:

From the question given above, the following data were obtained:

Height (h) = 1 m

Time (t) =?

Velocity (v) =?

1. Determination of the time taken for the pencil to hit the floor.

Height (h) = 1 m

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) =?

h = ½gt²

1 = ½ × 9.8 × t²

1 = 4.9 × t²

Divide both side by 4.8

t² = 1/4.9

Take the square root of both side

t = √(1/4.9)

t = 0.45 s.

Thus, it will take 0.45 s for the pencil to hit the floor.

2. Determination of the velocity with which the pencil hit the floor.

Initial velocity (u) = 0 m/s

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) = 0.45 s.

Final velocity (v) =?

v = u + gt

v = 0 + (9.8 × 0.45)

v = 0 + 4.41

v = 4.41 m/s

Thus, the pencil hit the floor with a velocity of 4.41 m/s

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You drop two balls from a tower, one of mass m and the other of mass 3m.
neonofarm [45]
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3 years ago
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