So platinum is a transition metal. In general transition metals are reducers, which means they can give the electrons they have, to the sodium atoms. Also in chemistry we look at sub orbitals rather that shells(2,8,8). So due to the energy from heat, the d orbital split as electrons move to a higher energy level. Some of the electrons are given to the sodium ions and therefore the flame changes colour to yellow.
The excitation of the electrons is caused by them getting energy and so moving up an energy level. This energy is released and the electron returns to it's original state. The energy released, however, does not release in the same direction, but in different/various directions. Therefore the colour of the light changes as some energy is released in the surrounding.
Answer:
Explanation:40 mph = 64.3738 kph
kph/3.6 = m/s
64.3738/3.6 = 17.8816 m/s
30 mins in seconds = 30 x 60 = 1800 s
1800 s x 17.8816 m/s = 32186.88 m or 32.18688 km or 20 miles
Answer:
Density is mass over volume.
Explanation:
Answer:
![\huge 3.322 \times {10}^{ - 5} \: \: moles \\](https://tex.z-dn.net/?f=%20%5Chuge%203.322%20%5Ctimes%20%20%7B10%7D%5E%7B%20-%205%7D%20%20%5C%3A%20%20%5C%3A%20moles%20%20%5C%5C%20)
Explanation:
To find the number of moles in a substance given it's number of entities we use the formula
![n = \frac{N}{L} \\](https://tex.z-dn.net/?f=n%20%3D%20%20%5Cfrac%7BN%7D%7BL%7D%20%5C%5C)
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question we have
![n = \frac{2.00 \times {10}^{19} }{6.02 \times {10}^{23} } \\ \\ = 3.322 \times {10}^{ - 5} \: \: moles](https://tex.z-dn.net/?f=n%20%3D%20%20%5Cfrac%7B2.00%20%5Ctimes%20%20%7B10%7D%5E%7B19%7D%20%7D%7B6.02%20%5Ctimes%20%20%7B10%7D%5E%7B23%7D%20%7D%20%20%5C%5C%20%20%5C%5C%20%20%3D%203.322%20%5Ctimes%20%20%7B10%7D%5E%7B%20-%205%7D%20%20%5C%3A%20%20%5C%3A%20moles)
Hope this helps you
Answer:
s an example, the ground state configuration of the sodium atom is 1s22s22p63s1, as deduced from the Aufbau principle (see below). The first excited state is obtained by promoting a 3s electron to the 3p orbital, to obtain the 1s22s22p63p1 configuration, abbreviated as the 3p level.
Explanation: