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vlada-n [284]
3 years ago
9

The molecular weight of table salt, NaCl, is 58.5 g/mol. A tablespoon of salt weighs 6.37 grams. Calculate the number of moles o

f salt in one tablespoon. Next, cancel like terms and units: Which of the following shows the correct terms and units canceled?
A>N>S: the 2nd one
Chemistry
2 answers:
Sati [7]3 years ago
8 0

Answer:

the second one

Explanation:

cestrela7 [59]3 years ago
3 0

Answer:

The number of moles of salt in one tablespoon is = <u>0.11 mole</u>

<u>Grams </u>cancel each other.

Explanation:

<u>Moles</u> : It is the unit of quantity . It is the mass of the substance present in exactly 12g of C-12.

moles=\frac{given\ mass}{Molar\ mass}

<u>Moles Calculation:</u>

Given mass = 6.37  gram

Molar mass = 58.5 g/mol

moles=\frac{6.37}{58.5}

= 0.1088

= 0.11 mole

<u>Units calculation</u>

moles=\frac{given\ mass}{Molar\ mass}

moles=\frac{g}{g/mole}

moles=\frac{g}{g}\times mole

<u>g ang g cancels each other </u>

moles = moles

<u>Hence unit = gram (g ) cancel each other.</u>

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pickupchik [31]

Answer:

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equation

8000 (number of meters) divided by 1609.34 ( equivalent of miles in one meter)

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Which of the following is the correct set-up for the problem: How many grams of water will be produced from 3.2 moles of oxygen
suter [353]

Option C is the correct set of the problem for mass of water produced by 3.2 moles of oxygen and an excess ethene.

<h3>Reaction between oxygen and ethene</h3>

Ethene (C2H4) burns in the presence of oxygen (O2) to form carbon dioxide (CO2) and water (H2O) along with the evolution of heat and light.

C₂H₄  + 3O₂   ----- > 2CO₂ + 2H₂O

from the equation above;

3 moles of O₂ ---------> 2(18 g) of water

3.5 moles of O₂ ----------> x

x = 3.2 \times [\frac{2 \ moles \ H_2O}{3 \ moles \ O_2}  ] \times[ \frac{18.02 \ g \ H_2O}{1 \ mole \ H_2O} ]

Thus, option C is the correct set of the problem for mass of water produced by 3.2 moles of oxygen and an excess ethene.

Learn more about reaction of ethene here: brainly.com/question/4282233

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The reform reaction between steam and gaseous methane (CH4) produces "synthesis gas," a mixture of carbon monoxide gas and dihyd
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Answer:

The answer is "= 0.078 \ kg \ H_2".

Explanation:

calculating the moles in CH_4 =\frac{PV}{RT}

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Eqution:

CH_4 +H_2O \to  3H_2+ CO \ (g)

Calculating the amount of H_2 produced:

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So, the amount of dihydrogen produced = 0.078 \frac{kg}{s}

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Answer:

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