As we know that, molecular mass of ferric oxide, Fe2O3, is 159.69 grams.
Out of which, iron contributes 111.69 g (2 X 55.845 g) and oxygen contributes
48 g (3 X 16 g).
Each gram of iron (III) oxide contains 111.69/159.69 g of iron and 48/159.69
g of oxygen.
To produce 1000 g iron (III) oxide we need,
Iron = 111.69*1000/159.69 = 699.42 g
Oxygen = 48*1000/159.69 = 300.58 g

6 0

3 years ago

the weatherman reports the storm waves are about 2 meters high and 35 meters apart. What properties of waves is the reporter des

8_murik_8 [283]

Answer:

Amplitude and wavelength

Explanation:

- The amplitude of a wave is the maximum displacement of the wave, measured with respect to the equilibrium position (so, for a water wave it is the maximum height of the wave relative to the equilibrium position)

- The wavelength of a wave is the distance between two consecutive crests (or throughs) of a wave. So, for a water wave, it is the distance between two consecutive waves

Therefore, in the example in the problem we have:

- 2 meters corresponds to the amplitude

- 35 meters corresponds to the wavelength

6 0

2 years ago

In his novel From the Earth to the Moon (1866), Jules Verne describes a spaceship that is blasted out of 12,000 yards/s. the Col

saw5 [17]

Answer:

The acceleration experienced by the occupants of the spaceship during launch is 282652.782 meters per square second.

Explanation:

Let suppose that spaceship is accelerated uniformly. A yard equals 0.914 meters. A feet equals 0.304 meters. If air viscosity and friction can be neglected, then acceleration ( $a$ ), measured in meters per square second, is estimated by this kinematic formula:

$a = \frac{v^{2}-v_{o}^{2}}{2\cdot \Delta s }$ (1)

Where:

$\Delta s$ - Travelled distance, measured in meters.

$v_{o}$ , $v$ - Initial and final speeds of the spaceship, measured in meters.

If we know that $v_{o} = 0\,\frac{m}{s}$ , $v = 10968\,\frac{m}{s}$ and $\Delta s = 212.8\,m$ , then the acceleration experimented by the spaceship is: