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frez [133]
3 years ago
12

How much force is required to accelerate a .6 kg object at 5 m/s^2

Physics
1 answer:
vodomira [7]3 years ago
7 0

Answer:

.

» 30 N

Explanation:

<u>Given</u> :

Mass → m → 6kg

Acceleration → a →

5 {ms}^{ - 2}

<u>To</u><u> </u><u>find</u> :

The formula for force

F = m • a

F = 6 • 5

F = 30 N

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Ostrovityanka [42]

The correct answer is:

Work is negative, the environment did work on the object, and the energy of the system decreases.

In fact, the work-energy theorem states that the work done by the system is equal to its variation of kinetic energy:

W=\Delta K=K_f -K_i

In this problem, the variation of kinetic energy \Delta K is negative (because the final velocity is less than the initial velocity), so the work is negative, and this means that the environment did work on the object, and its energy decreased.

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2 years ago
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You have four fixed-volume containers at STP . Container A has 0.5 mol of gas in 11.2 L. Container B has 2 mol of gas in 22.4 L.
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Answer:

Container A and C

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2 years ago
A small person was running way faster than a bigger person that weighed more collided in a football game. Who would be pushed ba
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Answer:

smaller one

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3 years ago
The intensity level is 65 db at a distance 5.00 m from a barking dog. What would be a reasonable estimate for the intensity leve
BARSIC [14]

Answer:

68 db

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Ignoring interference effects, the barking of two dogs result in a higher level of intensity which is given by,

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2. A person began running due east and covered 15 kilometers in 2.0 hours. What is the average velocity of the person?
Angelina_Jolie [31]

Answer:

7.5 km/h (2.1 m/s) due east

Explanation:

The average velocity of the person is given by:

v=\frac{d}{t}

where

d is the displacement

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In this problem,

d = 15 km is the displacement

t = 2.0 h is the time elapsed

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We can also convert the velocity into SI units (m/s). We have:

d = 15 km = 15,000 m

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