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3 years ago

6. Find the magnetic field strength at the centre of a solenoid with

Physics

1 answer:

inysia [295]3 years ago

8 0

Answer:

0.03 T

Explanation:

The magnetic field B at the center of a solenoid is given by B = μ₀Ni/L where

μ₀ = permeability of free space = 4π × 10⁻⁷ H/m, N = number of turns of solenoid = 5000 turns, i = current in solenoid = 5 A and L= length of solenoid. Since we are not given length of solenoid, let us assume it is 1 meter. So, L = 1 m

So, B = μ₀Ni/L

= 4π × 10⁻⁷ H/m × 5000 turns × 5 A/1m

= 4π × 10⁻⁷ H/m × 25000 A-turns/m

= 314159.27 × 10⁻⁷ T

= 0.031415927 T

≅ 0.03 T

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3. What is the force of sliding friction

ale4655 [162]

Answer:

the force of the friction is A-0.52

3 0

3 years ago

He throws a second ball (B2) upward with the same initial velocity at the instant that the first ball is at the ceiling. c. How

Gwar [14]

Answer:

hello your question has some missing parts

A juggler performs in a room whose ceiling is 3 m above the level of his hands. He throws a ball vertically upward so that it just reaches the ceiling.

answer : c) 0.39 sec

d) 2.25 m

e) 1.92 m/sec

Explanation:

The initial velocity of the first ball = 7.67 m/sec ( calculated )

Time required for first ball to reach ceiling = 0.78 secs ( calculated )

Determine how long after the second ball is thrown do the two balls pass each other

Distance travelled by first ball downwards when it meets second ball can be expressed as : d = 1/2 gt^2 = 9.8t^2 / 2

hence d = 4.9t^2 ----- ( 1 )

Initial speed of second ball = first ball initial speed = 7.67 m/sec

3 - d = 7.67t - 4.9t ---- ( 2 )

equating equation 1 and 2

3 = 7.67t therefore t = 0.39 sec

Determine how far the balls are above the Juggler's hands ( when the balls pass each other )

form equation 1 ;

d = 4.9 t^2 = 4.9 *(0.39)^2 = 0.75 m

therefore the height the balls are above the Juggler's hands is

3 - d = 3 - 0.75 = 2.25 m

determine their velocities when the pass each other

velocity = displacement / time

velocity = d / t = 0.75 / 0.39 sec = 1.92 m/sec

7 0

3 years ago

Find the difference between two masses measured as 123.6 grams and 115.972 grams. Express the answer to the correct number of si

xxTIMURxx [149]

Answer:

The difference is 7.6 grams.

Explanation:

In mathematics the difference of two numbers is express as the subtraction between them:

$a-b$

So to find out the difference between the two measured masses, a will be represented by 123.6 grams since is the bigger number, and b by 115.972 grams.

Therefore, it is get:

$123.6grams-115.972grams = 7.6grams$