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max2010maxim [7]
3 years ago
10

A group of students decides to set up an experiment in which they will measure the specific heat of a small amount of metal. The

metal has a mass of about 5 grams.
They hang the metal in a beaker of boiling water for a long time (10 minutes or so). Then, they very quickly (within a few seconds) remove the metal from the boiling water and transfer it to a styrofoam cup of 150 mL of water at room temperature. There is a thermometer in the styrofoam cup. They know that the rise in temperature will tell them what they need to know in order to determine the specific heat of the metal, so they watch the thermometer closely... but nothing happens. The temperature does not appear to change at all.

Each student has a different suggestion for how to improve the experiment. Which of the suggestions is least likely to help?

A. Use less room temperature water in the styrofoam cup
B. Use more metal (50 grams instead of 5 grams)
C. Use more boiling water in the first beaker
D. Use a more sensitive thermometer.
Physics
1 answer:
lesya692 [45]3 years ago
7 0
I think the answer is C
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3 years ago
From the circuit above, predict which bulb (or bulbs) will be the brightest. Why do you think that?
inysia [295]

Answer:

the middle

Explanation:

the left one bulb gets power from the outher bulb

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7 0
3 years ago
Read 2 more answers
A small branch is wedged under a 200 kg rock and rests on a smaller object. The smaller object is 2.0 m from the large rock and
Alexxandr [17]

Answer:

a

  F  =326.7 \ N

b

  M  = 6

Explanation:

From the question we are told that

          The mass of the rock is  m_r  =  200 \ kg

          The  length of the small object from the rock is  d  =  2 \ m

          The  length of the small object from the branch l  =  12 \ m

An image representing this lever set-up is shown on the first uploaded image

Here the small object acts as a fulcrum

The  force exerted by the weight of the rock is mathematically evaluated as

      W =  m_r *  g

substituting values

     W =   200 *  9.8

     W =   1960 \ N

 So  at  equilibrium the sum  of the moment about the fulcrum is mathematically represented as

         \sum  M_f  =  F * cos \theta *  l  -  W cos\theta  *  d =  0

Here  \theta is very small so  cos\theta  *  l  =  l

                               and  cos\theta  *  d  =  d

Hence

       F *   l  -  W  * d =  0

=>    F  = \frac{W * d}{l}

substituting values

        F  = \frac{1960 *  2}{12}

       F  =326.7 \ N

The  mechanical advantage is mathematically evaluated as

          M  = \frac{W}{F}

substituting values

        M  = \frac{1960}{326.7}

       M  = 6

6 0
3 years ago
PLEASE HELP MEE PLEASE I BEG
TEA [102]

Explanation: (I think)

Plug your values into the momentum equation.

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8 0
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When light of wavelength 240 nm falls on a potassium surface, electrons having a maximum kinetic energy of 2.93 eV are emitted.
olchik [2.2K]

A) We want to find the work function of the potassium. Apply this equation:

E = 1243/λ - Φ

E = energy of photoelectron, λ = incoming light wavelength, Φ = potassium work function

Given values:

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Plug in and solve for Φ:

2.93 = 1243/240 - Φ

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B) We want to find the threshold wavelength, i.e. find the wavelength such that the energy E of the photoelectrons is 0eV. Plug in E = 0eV and Φ = 2.25eV and solve for the threshold wavelength λ:

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Given values:

c = 3×10⁸m/s, λ = 5.52×10⁻⁷m

Plug in and solve for f:

3×10⁸ = f(5.52×10⁻⁷)

f = 5.43×10¹⁴Hz

7 0
3 years ago
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