Answer: Ok, first lest see out problem.
It says it's a Long cylindrical charge distribution, So you can ignore the border effects on the ends of the cylinder.
Also by the gauss law we know that E¨*2*pi*r*L = Q/ε0
where Q is the total charge inside our gaussian surface, that will be a cylinder of radius r and heaight L.
So Q= rho*volume= pi*r*r*L*rho
so replacing : E = (1/2)*r*rho/ε0
you may ask, ¿why dont use R on the solution?
since you are calculating the field inside the cylinder, and the charge density is uniform inside of it, you don't see the charge that is outside, and in your calculation actuali doesn't matter how much charge is outside your gaussian surface, so R does not have an effect on the calculation.
R would matter if in the problem they give you the total charge of the cylinder, so when you only have the charge of a smaller r radius cylinder, you will have a relation between r and R that describes how much charge density you are enclosing.
Answer:
A signal is produced.
Radio waves are modulated and amplified.
Radio waves are amplified and demodulated.
A signal is seen, heard, or used.
Explanation:
Communication is the method of transmitting information between two or more participants. A radio communication network is a set of static and wireless radio equipment developed to facilitate an entity by enabling particular modes of communication such as one-to-many and one-to-one communication. Radio waves are being used to transmit information spatially from the sender to receiver, by modulating the radio signal in the transmitter. The above steps explains the loop of the radio communication system.
Answer:
2000 For The First/900 For The Second/And 2000 For The Third/JUST TOOK QUIZ
Explanation:
Answer:
can you show a graph but if not i believe the answer is x=6m
Explanation:
Answer:
Therefore, the revolutions that each tire makes is:

Explanation:
We can use the following equation:
(1)
The angular acceleration is:



and the initial angular velocity is:



Now, using equation (1) we can find the revolutions of the tire.

Therefore, the revolutions that each tire makes is:

I hope it helps you!