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sineoko [7]
3 years ago
13

3. An explosion of gas from a Hawaiian volcano blows a bunch of rocks into the sky. Each has 2000J of

Physics
1 answer:
anzhelika [568]3 years ago
4 0

Answer: 3.906kg

Explanation:

K.E = 2000J

V = 32m/s

m =?

K.E = 1/2MV2

2000 = 1/2M x (32^2)

2000 = 1/2M x 1024

2000 = 512M

M = 2000/512

M = 3.906kg

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kodGreya [7K]
Selection D makes most sense
8 0
3 years ago
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George Washington Gale Ferris, Jr., a civil engineering graduate from Rensselaer Polytechnic Institute, built the original Ferri
MA_775_DIABLO [31]

Answer:

KE = 4217 J

Explanation:

As we know that the wheel is rotated at constant angular speed

so here we can say that the angular speed is given as

\omega = \frac{2\pi}{T}

\omega = \frac{2\pi}{2 \times 60}

\omega = 0.052 rad/s

now the moment of inertia of all passengers is given as

I = 36(60)(\frac{76}{2})^2

I = 3119040 kg m^2

now work done by machine must be equal to kinetic energy of the system

so we will have

KE = \frac{1}{2}I\omega^2

KE = \frac{1}{2}(3119040)(0.052)^2

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7 0
3 years ago
You stand on a bridge above a river and drop a rock into the water below from a height of 35m (assume no air resistance)
Katyanochek1 [597]

Answer:

Free fall time t:

2.6717061011357 sec

Free fall velocity v:

26.200486636702 m/s    

= 94.321751892127    km/h    

Explanation:

6 0
3 years ago
A 1 kg ball is loaded into a spring gun with a spring constant of 105 N/m. If the spring iscompressed by 0.1 m and the ball is s
Rainbow [258]

Answer:

H = 5.35 cm

Explanation:

As per energy conservation we know that energy stored in the spring is converted into gravitational potential energy when it is reached at the top

now we have

\frac{1}{2}kx^2 = mgh

here we know that

m = 1 kg

k = 105 N/m

x = 0.1 m

now plug in all data in it

\frac{1}{2}(105)(0.1^2) = 1(9.81)(H)

now solving for height H we have

H = 0.0535 m

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3 0
3 years ago
The sideview mirrors on cars are convex mirrors. Let's say the mirror on the driver's side of your car has a focal length with a
Arisa [49]

Answer:

a)  i = -2.53 m , b)  m = 0.63

Explanation:

a) For this exercise we use the constructor equation

     1 / f = 1 / o + 1 / i

Where f is the focal length, o the distance to the object and i the distance to the image

In this exercise they give the focal length f = -6.90 m, the negative sign is a convex mirror, and the distance to the object is o = 4.00 m

 Let's find the distance to the image

         1 / i = 1 / f - 1 / o

         1 / i = 1 / -6.90 - 1/4

          1 / i = -0.1449-0.25 = 0.3949

          i = -2.53 m

.b) the expression for the magnification is

          m = - i / o

          m = - (-2.53) / 4

          m = 0.63

6 0
3 years ago
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