<em>Answer:</em>
There are two major resonance contributors for the en-amine. One contributor have no formal charges, only have one lone pair at N while the other one has positive and negative formal charges.
<em>Explanation:</em>
An en-amine is formed by the condensation reactions of aldehydes or ketone with secondary amine.
The contributor<em> </em>I have no formal charges. It has only one lone pair at Nitrogen atom.
The contributor II has +1 formal charges at N, and -1 formal charges at α Carbon.
Please see attachment. The resonance contributor are given.
Answer:
A. light energy is used in photosynthesis and created by respiration
Amobarbital (like all barbiturates) works by being incontestible to the GABAA receptor at either the alpha or the beta subunit.
<h3>What is the mechanism of amobarbital?</h3>
Amobarbital (like all barbiturates) works by binding to the GABAA receptor at either the alpha or the beta subunit. These are compulsory sites that are distinct from GABA itself and also distinct from the benzodiazepine binding site.
Amobarbital is a barbiturate classified as having a halfway duration of action, meaning that the effects of the drug can last from 4-6 amobarbital increases the effects of benazepril by apparatus: pharmacodynamic synergism.
So we can conclude that Amobarbital, 5-ethyl-5-isoamyl barbituric acid like all barbiturates.
Learn more about Amobarbital here: brainly.com/question/7237163
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Answer:
any atom that contains six protons is the element carbon and has the atomic number 6, regardless of how many neutrons or electrons it may have.
Explanation:
