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Phantasy [73]
3 years ago
10

Just helping as usual what about you​

Physics
2 answers:
7nadin3 [17]3 years ago
6 0

Answer:

same i just love helping people out

god bless you have a blessed day

Explanation:

VMariaS [17]3 years ago
6 0

Answer:

I do too

Explanation:

I like to help others especially if it has been filled in by struggling in a certain concept of a subject.

Do u agree?

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Which of the following represents a case in which you are not accelerating? View Available Hint(s) Which of the following repres
padilas [110]

Answer:

4) Driving in a straight line at 60 miles per hour

Explanation:

1) Driving 60 miles per hour around a curve

2) Going from 0 to 60 miles per hour in 10 seconds

3) Slamming on the brakes to come to a stop at a stop sign

4) Driving in a straight line at 60 miles per hour

1) The speed is constant here, but in circular motion you have an acceleration that is v^2/r, where v is the speed and r the radius

2) You are accelerating from 0 to 60

3) You are desaccelerating

4) constant speed , no acceleration  

8 0
3 years ago
A 5.00-g bullet leaves the muzzle of a rifle with a speed of 320 m/s. the expanding gases behind it exert what force on the bull
muminat

Answer;

= 312 Newtons

Explanation;

The bullet has a mass of 0.005 kg, and a velocity of 320 m/s, so we need to find it's final kinetic energy.  

KE = 1/2*m*v^2

      = 1/2*0.005*320^2

      = 256 Joules.  

Divide this by the distance over which this energy was received and you have the force that provided that energy.  

  = 256/0.820 = 312.195 Newtons  

Rounded off, this is 312 N

3 0
3 years ago
A solid nonconducting sphere of radius R carries a charge Q distributed uniformly throughout its volume. At a certain distancer1
Jobisdone [24]

Answer:

The magnitude of the electric field in the second case will be \frac{1}{8} of the electric field in the first case

Explanation:

The electric field at a distance r_1 < R from the center of the sphere is given by

the formula E_1  = \frac{kQr_1}{R^3}  

where R is the radius of the sphere, and, Q is the charge uniformly distributed on the sphere.

It is given that the same charge Q is distributed uniformly throughout a sphere of radius 2R and we have to find the electric field at same distance r_1 from the center.

In the second case the electric field will be given by

E_2 = \frac{kQr_1}{(2R)^3}  = \frac{kQr_1}{8R^3}  =\frac{1}{8}  \frac{kQr_1}{R^3} = \frac{1}{8} E_1

Therefore the magnitude of the electric field in the second case will be \frac{1}{8} of the electric field in the first case.

4 0
4 years ago
What would u expect the tides to be like during a first quarter moon?
kicyunya [14]

Answer:

During the first quarter or last quarter phase of the moon, when the sun and moon are perpendicular (at right angles) to each other in relation to the Earth, the tidal gravitational pulls interfere with each other, producing weaker tides, known as neap tides.

Explanation:

3 0
3 years ago
Read 2 more answers
What is the force of gravity on a 24.0 kg table sitting on the earth
marysya [2.9K]

Answer:

<h2>24×<u><em>9.8</em></u></h2><h2><u><em></em></u></h2>

Explanation:

4 0
3 years ago
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