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4 years ago

. Find the velocity in meters per second of a baseball thrown 38 m from third base to

Physics

2 answers:

Slav-nsk [51]4 years ago

5 0

Answer: v=22.35m/s

Explanation:

v=d/t or v= change in speed/change in time

V=38m/1.7s

zlopas [31]4 years ago

4 0

Answer:22.35m/s

Explanation:

Distance=38m

Time=1.7seconds

Velocity=distance ➗ time

Velocity=38 ➗ 1.7

Velocity=22.35m/s

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Answer:

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3 years ago

lesya692 [45]

Answer:

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Explanation:

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3 years ago

Read 2 more answers

an airplane is flying through a thundercloud at a height of 2000m (this is very dangerous thing to do because of updrafts, turbu

Vedmedyk [2.9K]

Answer

In this question we have given,

Height of plane, h1=2000m

Height at which charge concentration is 40C, h2=3000m

Height at which charge concentration is -40C, h3=1000m

charge concentaration, q1=40C

charge concentaration, q2=-40C

let the charge concentrations at height h2 and h3 as point charges

Now we will first find the electric feild on plane due to positive charge q1=40

$E1= k*q1/(h1-h2)..............(1)$

Here k=8.98755*10^9N.m^2/C^2

q1=40C

put values of k, q1 , h1 and h2 in equation 1

$[tex]E1=(8.98755*10^9)*(40)/(2000-3000)^2$ \\

$E1=[tex]E= 359502+359502\\E=719004 V/m$ V/m[/tex]

similarly electric feild due to negative charge q2=-40

$[tex]E2=(8.98755*10^9)*(-40)/(2000-1000)^2$ \\

$E2=359502V/m$

Total electric feild E at the aircraft is given as

$E= E1+ E2\\$ ...............(2)

Put values of E1 and E2 in equation2

$\\E=359502+359502\\E= 719004V/m\\$

therefore s Total electric feild E at the aircraft is E= 719004V/m

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3 years ago

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3 years ago

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Answer:

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