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lord [1]
3 years ago
5

Solve x2 + 8x − 3 = 0 using the completing-the-square method.

Mathematics
1 answer:
ICE Princess25 [194]3 years ago
4 0

Answer:

Step-by-step explanation:

x^2+8x-3=0 (move constant to other side by adding 3 to each side)

x^2+8x=3 (halve thr linear coefficient, square it and add to each side, (8/2)^2=16)

x^2+8x+16=3+16 (now the left side is a perfect square)

(x+4)^2=19 (now take the square root of each side)

x+4=+-(19^(1/2)) (finally subtract the constant to isolate x by itself)

x= -4+-(19^(1/2))

x=negative four plus or minus the square root of nineteen

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Suppose that a company has just purchased a new computer for $1500 The company chooses to depreciate using the straight-line met
agasfer [191]

<u>Solution-</u>

The company purchased a new computer for $1500 and chooses to depreciate using the straight-line method for 5 years.

a-

As the value is depreciating, so its slope will be -ve.

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y-intercept = 1500           ( ∵ At the beginning when x=0, y=1500)

Linear equation of the system,

y = mx +c ,

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y=-300x+1500

\Rightarrow y=1500-300x


b-

The implied domain of the function is 1≤x≤5 or [1,5]


c-

Follow the attachment attached herewith for the graph.


d-

Here,

y = the value of the computer

.

x = number of years depreciated = 3

Putting the values in the linear equation,

y = 1500-300(3) = 1500-900 = 600

∴  The book value of the computer after 3 years is $600.


e-

Here given that,

y = value of computer = 1600

x = asked = ??

Putting the values in the equation,

1600 = 1500 - 300x

⇒ 100= -300x

⇒ x= -3

∴ As the x is in negative, i.e it is impossible for the computer to be worth of 1600. It happens also because as the value is depreciating, it will always be less than 1500.



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