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Stels [109]
3 years ago
11

If a gas is pumped from a smaller container to a container that is twice the size, and its pressure is kept the same, then what

happens to the temperature of the gas?
Chemistry
1 answer:
raketka [301]3 years ago
3 0

Answer: If a gas is pumped from a smaller container to a container that is twice the size, and its pressure is kept the same, then temperature of the gas increases twice.

Explanation:

Charles law states that at constant pressure, the volume of a gas is directly proportional to the temperature.

That is, V \propto T.

So, when a gas is pumped from a smaller container to a container that is twice the size shows that volume is increasing by 2 times and its pressure is kept the same.

Therefore,

2V \propto 2T

This means that the temperature of the gas will also become twice its initial temperature.

Thus, we can conclude that if a gas is pumped from a smaller container to a container that is twice the size, and its pressure is kept the same, then temperature of the gas increases twice.

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What is the pH of a solution prepared by dissolving<br>0.8 g NaOH in water to make 200 mL solution?​
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pH>7

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Why was the weight of the fire snake slightly less after it was lit on fire
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8 0
3 years ago
To plot the calibration curve, you need to prepare iron solutions with known concentrations and measure their absorbance.
kap26 [50]

To plot the calibration curve, you need to prepare iron solutions with known concentrations and measure their absorbance. You need to pipet 0 mL of the diluted solution to have 0.00 mg of iron.

In spectrophotometry, to plot the calibration curve, you need to prepare solutions with known concentrations and measure their absorbance.

We have a standard iron solution with a concentration of 0.2500g/L of pure iron (C₁). We pipet 25.00mL (V₁) of this standard iron solution into a 500mL (V₂) volumetric flask and dilute up to the mark with distilled water.

We can calculate the concentration of the diluted solution (C₂) using the dilution rule.

C_1 \times V_1 = C_2 \times V_2\\\\C_2 = \frac{C_1 \times V_1}{V_2}  = \frac{0.2500 g/L \times 25.00 mL}{500 mL} = 0.0125 g/L

Then, if we wanted to prepare the blank, that is, the solution that contains the same matrix but not the analyte, and whose concentration in iron is 0.00 mg/L, we wouldn't pipet any of the diluted solution.

To plot the calibration curve, you need to prepare iron solutions with known concentrations and measure their absorbance. You need to pipet 0 mL of the diluted solution to have 0.00 mg of iron.

Learn  more: brainly.com/question/24195565

8 0
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