How many grams of water would require 2200 joules of heat to raise it’s temperature from 34 degrees Celsius to 100 degrees celsi
1 answer:
Answer:
Mass, m = 7.97 grams
Explanation:
We have,
Initial temperature was 34 degrees Celsius
Heat produced in it is 100 calories of heat
The specific heat capacity of water is 4.18 J/g °C
The heat produced due to change in temperature is given by :
m is mass of water in grams
So, 7.97 grams of water is required to produce heat of 2200 joules.
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Answer:
a) ΔGrxn = 6.7 kJ/mol
b) K = 0.066
c) PO2 = 0.16 atm
Explanation:
a) The reaction is:
M₂O₃ = 2M + 3/2O₂
The expression for Gibbs energy is:
ΔGrxn = ∑Gproducts - ∑Greactants
Where
M₂O₃ = -6.7 kJ/mol
M = 0
O₂ = 0
b) To calculate the constant we have the following expression:
Where
ΔGrxn = 6.7 kJ/mol = 6700 J/mol
T = 298 K
R = 8.314 J/mol K
c) The equilibrium pressure of O₂ over M is: