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anzhelika [568]
2 years ago
8

How many grams of water would require 2200 joules of heat to raise it’s temperature from 34 degrees Celsius to 100 degrees celsi

us ? The specific heat of water is 4.18 j/gC ?
Chemistry
1 answer:
Arada [10]2 years ago
7 0

Answer:

Mass, m = 7.97 grams

Explanation:

We have,

Initial temperature was 34 degrees Celsius

Heat produced in it is 100 calories of heat

The specific heat capacity of water is 4.18 J/g °C

The heat produced due to change in temperature is given by :

Q=mc(T_f-T_i)

m is mass of water in grams

m=\dfrac{Q}{c(T_f-T_i)}\\\\m=\dfrac{2200}{4.18\times (100-34)}\\\\m=7.97\ g

So, 7.97 grams of water is required to produce heat of 2200 joules.

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Alenkasestr [34]

Answer: Thus concentration of Ca(OH)_2 in mol/dm^3  is 0.011 and in g/dm^3 is 0.814

Explanation:

To calculate the concentration of Ca(OH)_2, we use the equation given by neutralization reaction:

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n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HCl

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n_1=1\\M_1=0.06mol/dm^3\\V_1=11cm^3=0.011dm^3\\n_2=2\\M_2=?\\V_2=30cm^3=0.030dm^3         1cm^3=0.001dm^3

Putting values in above equation, we get:

1\times 0.06mol/dm^3\times 0.011dm^3=2\times M_2\times 0.030dm^3\\\\M_2=0.011mol/dm^3

The concentration in g/dm^3 is 0.011mol/dm^3\times 74g/mol=0.814g/dm^3

Thus concentration of Ca(OH)_2 is 0.011mol/dm^3 and 0.814g/dm^3

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