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anzhelika [568]
2 years ago
8

How many grams of water would require 2200 joules of heat to raise it’s temperature from 34 degrees Celsius to 100 degrees celsi

us ? The specific heat of water is 4.18 j/gC ?
Chemistry
1 answer:
Arada [10]2 years ago
7 0

Answer:

Mass, m = 7.97 grams

Explanation:

We have,

Initial temperature was 34 degrees Celsius

Heat produced in it is 100 calories of heat

The specific heat capacity of water is 4.18 J/g °C

The heat produced due to change in temperature is given by :

Q=mc(T_f-T_i)

m is mass of water in grams

m=\dfrac{Q}{c(T_f-T_i)}\\\\m=\dfrac{2200}{4.18\times (100-34)}\\\\m=7.97\ g

So, 7.97 grams of water is required to produce heat of 2200 joules.

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alisha [4.7K]

H₂O would be the limiting reactant.

Balanced chemical equation:

6CO₂ + 6H₂O + light equation → C₆H₁₂O₆ + 6O₂

The amount of product that can be created is constrained by the reactant that is consumed first in a chemical reaction, commonly referred to as the limiting reactant (or limiting reagent).

Given

No. of moles of CO₂ = 18.6

Mass of H₂O = 2.38 × 10² g = 238g

No. of moles of H₂O = Given mass/ Molar mass

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Moles of H₂O = 13.22

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So the reactant that has less number of moles will be consumed first.

As the No. of moles of H₂O < No. of moles of CO₂

So, H₂O is the limiting reactant with 13.22 moles.

Hence, H₂O would be the limiting reactant.

Learn more about limiting reactant here brainly.com/question/14222359

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