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RSB [31]
3 years ago
9

A Person in Charge is required at food establishments: A. During the beginning of each shift B. During the end of each shift C.

During all hours of operation D. During the busy hours of operation
Chemistry
1 answer:
Dafna11 [192]3 years ago
7 0

Answer: C. During all hours of operation

Explanation:

The food establishments are the places such as restaurants, cafeterias, food stands and lunchrooms. The person in-charge of the food establishment should remain available at the establishments at all hours of operations. This is because the food establishment person in-charge usually has to look upon operations such as arrangement of the food raw materials, arrangement of kitchen, cooking food and serving it to clients. Such a person will also take into charge of making the bill and collecting the money.

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1.85 quarts can fit into a 1.75 liter bottle
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What type of elements are generally involved in covalent bonding?
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<span>In organic chemistry, covalent bonding is most often associated with carbon compounds, which are known as organic chemicals. Hydrogen is also involved most of the time, as well as oxygen. Other elements can also be involved, but less frequently.</span>
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3 years ago
Different isotopes of the same element emit light at slightly different wavelengths. A wavelength in the emission spectrum of a
Inessa [10]

Different isotopes of the same element emit light at slightly different wavelengths, the minimum number of slits  is mathematically given as

N=1820slits

<h3>What minimum number of slits is required to resolve these two wavelengths in second-order?</h3>

Generally, the equation for the wave is mathematically given as

d\ sin\ (\theta\ m) \ = \ m\  \lambda

Where the chromatic resolving power (R) is defined by

R\  =\ \lambda\ / \ d \  \lambda

R = nN,

Therefore

\lambda_1 \ = \  (656.45)(1 \ * \ 10^{-9})/1mm

\lambda_1= 656.45*10^{-9}

and

\lambda_2= (656.27)(1*10^{-9})/1mm

\\\\\lambda_2= 656.27*10^{-9}m

In conclusion, the minimum number of slits is required to resolve these two wavelengths in second-order

N\ =\ \dfrac{\lambda}{m\ d\ T\ }\\\\

Therefore

N\ =\ \dfrac{656.45 \ * \ 10^{-9}}{2\ * \ (0.18*10^{-9})}

N=1820slits

Read more about slits

brainly.com/question/24305019

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7 0
2 years ago
A 4.0 L container holds a sample of hydrogen gas at 306 K and 150 kPa. If the pressure increases to 300 kPa and the volume remai
riadik2000 [5.3K]

Answer:

612 K

Explanation:

From the question given above, the following data were obtained:

Initial temperature (T₁) = 306 K

Initial pressure (P₁) = 150 kPa

Final pressure (P₂) = 300 kPa

Volume = 4 L = constant

Final temperature (T₂) =?

Since the volume is constant, the final (i.e the new) temperature of the gas can be obtained as follow:

P₁ / T₁ = P₂ / T₂

150 / 306 = 300 / T₂

Cross multiply

150 × T₂ = 306 × 300

150 × T₂ = 91800

Divide both side by 150

T₂ = 91800 / 150

T₂ = 612 K

Thus, the new temperature of the gas is 612 K

4 0
3 years ago
Please help me with this question!! read the photo
pishuonlain [190]

There are 1.92 × 10^23 atoms Mo in the cylinder.

<em>Step 1</em>. Calculate the <em>mass of the cylinder </em>

Mass = 22.0 mL × (8.20 g/1 mL) = 180.4 g

<em>Step 2</em>. Calculate the<em> mass of Mo </em>

Mass of Mo = 180.4 g alloy × (17.0 g Mo/100 g alloy) = 30.67 g Mo

<em>Step 3</em>. Convert <em>grams of Mo</em> to <em>moles of Mo </em>

Moles of Mo = 30.67 g Mo × (1 mol Mo/95.95 g Mo) = 0.3196 mol Mo

<em>Step 4</em>. Convert <em>moles of M</em>o to <em>atoms of Mo </em>

Atoms of Mo = 0.3196 mol Mo × (6.022 × 10^2<em>3</em> atoms Mo)/(1 mol Mo)

= 1.92 × 10^23 atoms Mo

7 0
3 years ago
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