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RSB [31]
3 years ago
9

A Person in Charge is required at food establishments: A. During the beginning of each shift B. During the end of each shift C.

During all hours of operation D. During the busy hours of operation
Chemistry
1 answer:
Dafna11 [192]3 years ago
7 0

Answer: C. During all hours of operation

Explanation:

The food establishments are the places such as restaurants, cafeterias, food stands and lunchrooms. The person in-charge of the food establishment should remain available at the establishments at all hours of operations. This is because the food establishment person in-charge usually has to look upon operations such as arrangement of the food raw materials, arrangement of kitchen, cooking food and serving it to clients. Such a person will also take into charge of making the bill and collecting the money.

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9. To become like a noble gas the element P will have a charge of
MrRa [10]

Answer:

to become a noble gas element P will have 2 electrons in it's outer most energy level if it has one energy level

and eight in the last energy level if more than one

6 0
3 years ago
Write the balanced equation for the reaction of aqueous Pb ( ClO 3 ) 2 with aqueous NaI . Include phases. chemical equation: Wha
Citrus2011 [14]

<u>Answer:</u> The mass of lead iodide produced is 9.22 grams

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

Molarity of NaI = 0.200 M

Volume of solution = 0.200 L

Putting values in above equation, we get:

0.200M=\frac{\text{Moles of NaI}}{0.200}\\\\\text{Moles of NaI}=(0.200mol/L\times 0.200L)=0.04moles

The chemical equation for the reaction of NaI and lead chlorate follows:

Pb(ClO_3)_2(aq.)+2NaI(aq.)\rightarrow PbI_2(s)+2NaClO_3(aq.)

By Stoichiometry of the reaction:

2 moles of NaI reacts produces 1 mole of lead iodide

So, 0.04 moles of NaI will react with = \frac{1}{2}\times 0.04=0.02mol of lead iodide

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Molar mass of lead iodide = 461 g/mol

Moles of lead iodide= 0.02 moles

Putting values in above equation, we get:

0.02mol=\frac{\text{Mass of lead iodide}}{461g/mol}\\\\\text{Mass of lead iodide}=(0.02mol\times 461g/mol)=9.22g

Hence, the mass of lead iodide produced is 9.22 grams

6 0
3 years ago
Hydroxyapatite, Ca 10 ( PO 4 ) 6 ( OH ) 2 , has a solubility constant of Ksp = 2.34 × 10 − 59 , and dissociates according to Ca
GenaCL600 [577]

Answer: 4M

Explanation:

5 0
3 years ago
How many grams of lead would be required to make 119 grams of water
Ludmilka [50]

Answer:

(119 g H2O) / (18.01532 g H2O/mol) x (1 mol Pb / 2 mol H2O) x (207.21 g Pb/mol) = 684 g Pb

Explanation:

8 0
3 years ago
Read 2 more answers
I need help on B-I. Please help quickly i have to go on the bus .
lions [1.4K]
Abiotic is the right answer
3 0
3 years ago
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