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Andre45 [30]
2 years ago
9

Overall force acting on an object.

Physics
1 answer:
arsen [322]2 years ago
3 0

Answer:

Gravity

Explanation:

Gravity is a force that acts upon every single object on Earth.

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How can you tell if an igneous rock has an intrusive or extrusive origin?
wariber [46]

Intrusive igneous rocks cool down from magma slowly because they form underneath the surface, that will make them have large crystals.

Extrusive igneous rocks cool down from lava rapidly because they form at the surface, so that will make them have small crystals.

4 0
3 years ago
What is the definition of electrical power?
Nonamiya [84]
An electric power measure the rate of electrical energy transfer by an electric circuit per unit of time.
6 0
2 years ago
how height does a 2.5 Kg object rises when 255J of work done against gravity A 637.5 B 20.5 C 15m D 10.2 m​
balu736 [363]

Answer:

D 10.2

Explanation:

255 ÷ 2.5= 10.2 or D

7 0
3 years ago
Read 2 more answers
4786 joules fer transferred to an 89.0 gram sample of a unknown material with an initial temperature of 23.0°C what is the speci
Alika [10]
Specific heat formula is Q=M*C*ΔT
Q is amount of energy (4786 J)
M is mass (89.0 g)
C is specific heat (unknown, answer will be in J/gºC)
ΔT is the change in temp (89.5-23.0=66.5ºC)
Let's plug it in.
4786=89.0(C)(66.5)
4786=5918.5(C)
/5918.5  
C=.8086508406 J/gºC
with sig figs...
C=.809 J/gºC
5 0
3 years ago
Read 2 more answers
A 0.140 m high cylinder
solmaris [256]

Answer:

The value of pressure inside the cylinder is 18.68 K Pa.

Explanation:

Given data

Height h = 0.14 m

Density \rho = 13600 \frac{kg}{m^{3} }

We know that

Pressure inside the cylinder is given by the formula

P = \rho g h ------- (1)

here

\rho = density of fluid = 13600 \frac{kg}{m^{3} }

g = acceleration due to gravity = 9.81 \frac{m}{s^{2} }

h = height of the cylinder = 0.14 m

Put all the values in above equation

P = 13600 × 9.81 × 0.14

P = 18678.24 Pa

P = 18.68 K Pa

Therefore the value of pressure inside the cylinder is 18.68 K Pa

5 0
3 years ago
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