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marusya05 [52]
3 years ago
11

Study the distance-time graph, showing the distances that eight different things cover in 120 seconds or less. The letters below

correspond to the lines on the graph. For each object, calculate the average speed, and then match it with the closest correct answer.
A:
B:
C:
D:
E:
F:
G:
H:

Physics
1 answer:
Diano4ka-milaya [45]3 years ago
8 0

Answer:

This question appear incomplete

Explanation:

This question appear incomplete because there is no list of closest correct answer there. Although can still be well attempted.

The formula to be used here is

average speed = distance ÷ time

The unit of speed here would be meters per second (m/s). However, some of the lines do not really fall on a measurable line on the graph and can only be "best assumed".

A: distance is 1600 meters

time appear to be 4 seconds (definitely less than 5 seconds according to the graph).

speed = 1600 ÷ 4

speed = 400 m/s

B: distance is 1600 meters

time appear to be 18 seconds (definitely less than 20 seconds according to the graph)

speed = 1600 ÷ 18

speed = 88.89 m/s

C: distance is 1600 meters

time is 65 seconds

speed = 1600 ÷ 65

speed = 24.62 m/s

D:  distance is 1600 meters

time is 105 seconds

speed = 1600 ÷ 105

speed = 15.24 m/s

E: distance is 1100 meters

time is 120 seconds

speed = 1100 ÷ 120

speed = 9.17 m/s

F: distance is 500 meters

time is 120 seconds

speed = 500 ÷ 120

speed = 4.17 m/s

G: distance appear to be 250 meters

time is 120 seconds

speed = 250 ÷ 120

speed = 2.08 m/s

H: distance appear to be 50 meters

time is 120 seconds

speed = 50 ÷ 120

speed = 0.42 m/s

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A ball is thrown upward at time t=0 from the ground with an initial velocity of 8 m/s (~ 18 mph). What is the total time it is i
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Answer:

The total time it is in the air for the ball is 1.6326 s

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To find:

the total time it is in the air = ?

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Solution:

A ball is thrown upward at time t=0 from the ground with an initial velocity of 8 m/s.

The time taken by the ball to reach the maximum height is given by,

t = \frac{v-u}{a}

Where t = time to reach maximum height

v = final velocity of the ball = 0 m/s

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Acceleration of gravity is taken as negative because ball is moving in opposite direction.

t = \frac{0-8}{-9.8}

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Thus, time taken by the ball to reach the ground again = time taken to reach maximum height

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Total time required for ball to reach ground = 1.6326 s

The total time it is in the air for the ball is 1.6326 s

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