List three physical properties of a soft drink
2 answers:
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Answer:
The acceleration of the electron is 1.457 x 10¹⁵ m/s².
Explanation:
Given;
initial velocity of the emitted electron, u = 1.5 x 10⁵ m/s
distance traveled by the electron, d = 0.01 m
final velocity of the electron, v = 5.4 x 10⁶ m/s
The acceleration of the electron is calculated as;
v² = u² + 2ad
(5.4 x 10⁶)² = (1.5 x 10⁵)² + (2 x 0.01)a
(2 x 0.01)a = (5.4 x 10⁶)² - (1.5 x 10⁵)²
(2 x 0.01)a = 2.91375 x 10¹³
Therefore, the acceleration of the electron is 1.457 x 10¹⁵ m/s².
Answer:
a = 0.77 m/s^2
Explanation:
The centripetal acceleration is given as
The velocity of the car can be calculated using the circumference of the track and the period of the car.
So, the acceleration is
Answer:
<em>The horizontal component of the velocity is 49.85 m/s.</em>
Explanation:
<u>Rectangular Components of a Vector</u>
A 2D vector can be expressed in several forms. The rectangular form gives its two components, one for each axis (x,y). The polar form gives the components as the pair (r,θ) being r the magnitude and θ the angle.
When the magnitude and angle of the vector are given, the rectangular components are calculated as follows:
Where v is the magnitude of the vector and θ is the angle with respect to the x positive direction.
The cart is moving at v=55 m/s at θ=25°, thus:
The horizontal component of the velocity is 49.85 m/s.