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3 years ago

Ayuda es urgente ya lalalalalalalalalalal

Mathematics

1 answer:

Crank3 years ago

8 0

Answer:

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Jasmine by 32 kiwi fruit for $16.How many kiwi can lisa buy if she has $6

zimovet [89]

The way to solve this is take 32/16, and you get 2. This means that you get 2 kiwis per dollar. So, if Lisa has $6, then she can buy 12 kiwis.

5 0

2 years ago

Find all solutions to the equation (sinx-cosx)^2=1

svetoff [14.1K]

Answer:

$x=\dfrac{\pi k}{2},\ k\in Z.$

Step-by-step explanation:

Simplify the equation $(\sin x-\cos x)^2=1:$

$\sin^2 x-2\sin x\cos x+\cos ^2x=1,\\ \\ (\sin^2x+\cos^2x)-2\sin x\cos x=1.\\$

Since

$\sin^2 x+\cos^2 x=1$

and

$2\sin x\cos x=\sin 2x,$

we have

$1-\sin 2x=1,\\ \\\sin 2x=0,\\ \\2x=\pi k,\ k\in Z,\\ \\x=\dfrac{\pi k}{2},\ k\in Z.$

8 0

3 years ago

Read 2 more answers

Of 7 Express in the form n : 1. Give n as a fully simplified fraction. 6:14

hjlf

Answer:

The ratio is;

3/7 : 1

Step-by-step explanation:

Here, we want to express the given ratio in the form n:1 where n is a fully simplified fraction

Mathematically, we have this by dividing both numbers by 14

That would be ;

6/14 : 14/14

= 3/7 : 1

3 0

2 years ago

What is the range of the following set? 46, 39, 49, 45, 42, 44, 41, 51, 40

gladu [14]

Answer:

Step-by-step explanation:

The range of a data set is just the difference between the largest and smallest values.

So, let's find the smallest value: it's 39. The largest value is 51.

Their difference is:

51 - 39 = 12

Thus, the answer is 12.

~ an aesthetics lover

6 0

2 years ago

Read 2 more answers

The height of a trapezoid is 6 in. and it’s area is 72 in to the 2nd power. One base of the trapezoid is 6 inches longer than th

Vitek1552 [10]

Given:

The height of the given trapezoid = 6 in

The area of the trapezoid = 72 in²

Also given, one base of the trapezoid is 6 inches longer than the other base

To find the lengths of the bases.

Formula

The area of the trapezoid is

$A=\frac{1}{2} (b_{1} +b_{2} )h$

where, h be the height of the trapezoid

$b_{1}$ be the shorter base

$b_{2}$ be the longer base

As per the given problem,

$b_{2}=b_{1} +6$

Now,

Putting, A=72, $b_{2}=b_{1}+6$ and h=6 we get,

$\frac{1}{2} (b_{1} +b_{1}+6)(6) = 72$

or, $b_{1}+b_{1}+6 = \frac{(72)(2)}{6}$

or, $2b_{1}+6 = 24$

or, $2b_{1}=24-6$

or, $b_{1}= \frac{18}{2}$

or, $b_{1}=9$

So,

The shorter base is 9 in and the other base is = (6+9) = 15 in

Hence,

One base is 9 inches for one of the bases and 15 inches for the other base.

5 0

3 years ago

Ayuda es urgente ya lalalalalalalalalalal​

Ayuda es urgente ya lalalalalalalalalalal